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3 years ago

4. Provide an example of a point that could NOT be a part of a function that includes the points:

Mathematics

1 answer:

nadezda [96]3 years ago

8 0

Answer:

(1, 6)

Step-by-step explanation:

While a function may NOT have two y-values assigned to the same x-value

(1,6) would not work because the x-value of 1 had already been used at the point (1,-3)

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Five men build a wall in 10 days how long will it take 10 men

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Answer:

5 Days ....thats easy....

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3 years ago

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Which of the following is the equation of a line perpendicular to the line y = -10x + 1, passing through the point (5,7)?

Viktor [21]

Line 1;
y=-10x+1
Gradient m= -10
Gradient of line 2= 1/10
$\frac{y-5}{x-7} = \frac{1}{10}$
y-5= $\frac{1}{10} {x-7}$
y-5= $\frac{1}{10} x- \frac{7}{10}$
y= $\frac{1}{10} x- \frac{43}{10}$

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3 years ago

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Solve ΔABC with ABC=51°, c=8 and a=11. Draw a diagram.

Rashid [163]

To solve a triangle means to obtain al the missing parts of the triangle.

<h3>How do you solve a triangle?</h3>

To solve a triangle means to obtain al the missing parts of the triangle. Now we have the following information;

<ABC = 51°

c = 8

a = 11

Then;

b^2 = a^2 + c^2 - 2acCos B

b^2 = (11)^2 + (8)^2 - [2 * 11 * 8 * cos 51]

b^2 = 121 + 64 - 55.38

b = 11.39

Now;

a/sinA = b/sinB

asinB = bsinA

sinA = asinB/b

sinA = 11 * sin 51/11.39

A = 48.6 or 49°

C = 180 - (49 + 51)

C = 80°

Learn more about triangles:brainly.com/question/2773823

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1 year ago

Suppose that scores on the mathematics part of a test for eighth-grade students follow a Normal distribution with standard devia

riadik2000 [5.3K]

Answer:

We need an SRS of scores of at least 153.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large an SRS of scores must you choose?

This is at least n, in which n is found when $M = 20, \sigma = 150$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$20 = 1.645*\frac{150}{\sqrt{n}}$

$20\sqrt{n} = 1.645*150$

$\sqrt{n} = \frac{1.645*150}{20}$

$\sqrt{n} = 12.3375$

$(\sqrt{n})^{2} = (12.3375)^{2}$

$n = 152.2$

Rounding to the next whole number, 153

We need an SRS of scores of at least 153.

8 0

2 years ago

What is equal to -5/4

sleet_krkn [62]

− 10/8

− 15/12

− 20/16

− 25/20

− 40/32

These are all equal, the list could go on but here are many

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3 years ago