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WINSTONCH [101]
3 years ago
9

Kyla climbed to a height of 10 ft from the bottom of a rock climbing wall. She then climbed up an additional 5 ft. Kyla must cli

mb down how many feet to return to the bottom of the climbing wall?
Mathematics
1 answer:
Ganezh [65]3 years ago
8 0

Answer:

15 ft

Step-by-step explanation:

10 + 5 = 15 ft

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The short sides of a rectangle are 2 inches. The long sides of the same rectangle are three less than an unknown
Brums [2.3K]

Answer:

The first student is correct

Step-by-step explanation:

With the given information there is already 4 inches on the rectangle. 13 x2 = 26. 26+4=30. For student two if the unknown number was 10 it would not work because the longest side is 3 less then the unknown number. 10-3=7. 7x2=14. 14+4= 28<30

8 0
3 years ago
What is 1.83 as a mixed fraction
lora16 [44]

Answer:

1\frac{83}{100}

Step-by-step explanation:

First of all, the number before the decimal would be the whole number of the fraction.

So, 1\frac{?}{?}

Then, you would put 0.83 over a fraction.

So because you cannot simplify it anymore, it would be 1\frac{83}{100}

6 0
3 years ago
Pls help I need a good grade <br><br><br> Z/5+3=-35<br><br> Show your work
Molodets [167]
Who is my work I think the answer would be -190

5 0
3 years ago
Help I WILL MARK IF RIGHT
melisa1 [442]

Answer:

0.95

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Can someone find r please
katrin2010 [14]

Answer:

r = 3 \times \sqrt{2}

Step-by-step explanation:

The area of the square is 36.

A = s^2

36 = s^2

s = sqrt(36)

s = 6

The side of the square has length 6.

All sides of a square are congruent, so all sides have length 6.

If you extend segment JO to point L, you end up with segment JL which is a diameter of the circle and the diagonal of the square. We can use the Pythagorean theorem using two sides if the square as legs and the diagonal of the square as the hypotenuse of a right triangle.

a^2 + b^2 = c^2

6^2 + 6^2 = c^2

36 + 36 = c^2

c^2 = 72

c = \sqrt{72}

c = \sqrt{36 \times 2}

c = \sqrt{36} \times \sqrt{2}

c = 6 \times \sqrt{2}

c is the diameter.

r is the radius, so it is half of the diameter.

c = d

r = d/2

r = \dfrac{d}{2} = 3 \times \sqrt{2}

8 0
3 years ago
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