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3 years ago

How do I solve this?

Mathematics

1 answer:

kobusy [5.1K]3 years ago

3 0

Answer:

3q^2/5p^4

Step-by-step explanation:

any variable/# w/a negative exponent is also 1/x^#

ex: p^-2 = 1/p^2 -> 9q^5/15p^4q^3

When dividing, you're subtracting the exponents

ex: q^5/q^3 = q^5-3 -> q^2

Lastly, simplify 9/15 to 3/5 -> 3q^2/5p^4

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Step-by-step explanation:

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liubo4ka [24]

we have to firstly apply the distance formula to find the length of sides of the triangle

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So length AB = $\sqrt{(-2-(-1))^2+(1-4)^2}= \sqrt{1 +9}=\sqrt{10}$

BC= $\sqrt{(2-(-2))^2+(1-1)^2}= \sqrt{16+0}=4$

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3 years ago

Can someoneee please help me

icang [17]

9514 1404 393

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37°

Step-by-step explanation:

The diagonals of a rhombus are angle bisectors. Angle 1 matches the other half of angle L.

∠1 = 37°

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Step-by-step explanation:

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