F(x)=1/(x-3)^3
The denominator can't be equal to zero (we can't divide by zero), then:
(x-3)^3 different 0
cubic root both sides:
cubic root [ (x-3)^3 ] different cubic root (0)
x-3 different 0
Adding 3 both sides:
x-3+3 different 0+3
x different 3
Then the function f is not defined at x=3
Answer: Option <span>b) f is not defined at x= 3</span>
All you have to do is make and simplify a fraction. In this case, there are 6 friends going into 4 pears, so the fraction is 6/4. Then we can simplify that because they are both divisible by 2. So if we divide both by 2, our fraction becomes 3/2. Then we make that into a mixed number, with 3 going into 2 once with 1 left over. That means the answer is 1 1/2.
The factors of polynomial are (x-1) and (x+3)
Step-by-step explanation:
If (x+9) is a factor of P(x)= x³+11x²+15x-27 then the P(x) must be completely divisible by (x+9)
After finding the polynomial, we need to factorise the polynomial by utilising the quadratic equation.
All the process has been described in image attached-
S₁, S₂, S₃ represents various steps involved in solving the problem.
It is found that (x+9) is a factor of x³+11x²+15x-27
The polynomial found after dividing x³+11x²+15x-27 by (x+9) is x²+2x-3
Which can be further factorised by quadratic rule into the factors as (x-1) and (x+3)
Hence the factors are (x-1) and (x+3)
Answer:
He is so cute
Step-by-step explanation:
X is equal to 7. Since you are trying to make them equal to each other, the denominator is already the same, so you just need to make the numerator the same too.
