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scZoUnD [109]
3 years ago
13

Write the expression add thirty-eight and fifty-two, then divide by four and half.

Mathematics
1 answer:
Licemer1 [7]3 years ago
5 0
This answer is 0.7037 that is the answer for this problem
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6squated - 3 squared
weeeeeb [17]

Answer:

27 is the answer to this equation

Step-by-step explanation:

6 times 6 equals 36

3times 3 equals 9

36

-9

27

7 0
3 years ago
Which is the MOST precise measurement this ruler can give for the green strip of paper? A) 4.00 inches B) 4.25 inches C) 4.50 in
Alenkinab [10]
The most precise is 4.00 because that is equal to 10.16 cm and that is the most closes to an exact measurment.
3 0
3 years ago
2+8<br><br> PLSSS HELP PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS
romanna [79]

Answer:

10

Step-by-step explanation

2 + 8= 10

6 0
3 years ago
Read 2 more answers
If some one could help me with these three questions I will be stoked!!!please please help me my teacher didn’t walk us through
salantis [7]

17) replace the given number for "x" and evaluate

a) x² + 2x + 1   ; when x = 3

  3² + 2(3) + 1

= 9 + 6 + 1

= 16

b) x² + 2x + 1   ; when x = -4

  (-4)² + 2(-4) + 1

= 16 - 8 + 1

= 9

c) x² + 2x + 1   ; when x = 3

  (-22.872)² + 2(-22.872) + 1

= 523.128384 - 45.744 + 1

= 478.384384

18) The dependent variable is affected by the other variable and is the "output"   The independent variable is the input.

a) y = 3x - 5;    "x" is the independent variable

b) the time of day is the independent variable  (you would input the time of day to calculate the temperature).

19) Let the x-axis represent the length of the lumber cut off and the y-axis represent the length of the lumber remaining.

5 0
4 years ago
Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located
arsen [322]
Check the picture below.

\bf \textit{using the pythagorean theorem}&#10;\\\\&#10;c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\&#10;-------------------------------

\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~  cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~  tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}&#10;\\\\\\&#10;csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}

3 0
3 years ago
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