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Bezzdna [24]
3 years ago
14

What is a condition in which the neuron membrane is more positive on the outside?

Biology
1 answer:
Elan Coil [88]3 years ago
4 0
Resting potential is when the outside is more positive, while the inside of the membrane is approximately -70mv
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1.______ from the sun is transferred to_____ surface. some of that energy is then _____
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1. Energy from the sun is transferred to earth's surface. Some of that energy is then transferred to the air above the surface.

2. The closer a location is to the equator the more energy it receives from the sun. Therefore a location's air temperature is affected by its distance from the equator.

3. An effect my have more than one cause. These may be linked into a chain of effects and causes.

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In eukaryotic cells, the timing of the cell cycle is regulated by…
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B)Cyclins regulate the timing of cell cycle

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What is the function of the red arrow ?
ch4aika [34]

Answer:

A. Mobility

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6 0
3 years ago
In a certain group of African people, 4% are born with sickle-cell disease, an autosomal recessive disorder. Heterozygous indivi
love history [14]

Answer:

the correct answer is C) 32%

Explanation:

Sickle-cell anaemia is an autosomal recessive genetic disorder. Individuals with the homozygous recessive have sickle-shaped blood cells. Whereas, individuals with heterozygous are only carrier of sickle cell trait. The carrier individuals are resistant to malarial parasite and do not have malaria.  

As per the question, 4% of an African population is born with sickle-cell disease, then the percentage of the population is heterozygous and resistant to malaria will be:  

Hardy-Weinberg formula is equilibrium,

        p² + 2pq + q² = 1  

p = frequency of the dominant allele in the population

q = frequency of the recessive allele in the population

p2 = percentage of homozygous dominant individuals

q2 = percentage of homozygous recessive individuals

2pq = percentage of heterozygous individuals

Given, homozygous recessive for this gene (q2) is 4%  which is 0.04, the square root (q) is 0.2 (20%) then p should be 1-0.2 = 0.8 (20%).  

Thus, the frequency of heterozygous individuals = 2pq.  

2 (0.8 x 0.2) = 0.32 (32%).  

4 0
3 years ago
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