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Oksi-84 [34.3K]
4 years ago
15

Find an equation for the nth Term of a geometric sequence where the second and fifth terms or -8 and 512, respectively

Mathematics
2 answers:
velikii [3]4 years ago
8 0

Answer:

Tn = -4^n/2

Step-by-step explanation:

The formula for nth tern of a geometric sequence is given as:

Tn = ar^n-1 where;

a is the first term

r is the common ratio

n is the number of terms

Since we are looking for the nth term if the geometric sequence, we will write our answer as a function if 'n'.

Given the second and fifth terms to be -8 and 512, respectively, this can be interpreted as;

T2 = ar^2-1 = -8

T5 = ar^5-1 = 512

From the equations above, we have;

ar = -8... (1)

ar⁴ = 512

Dividing both equation, we have;

ar⁴/ar = -512/8

r³ = -64

r = -4

Substituting r = -4 into equation 1, we have;

a(-4) = -8

-4a = -8

a = 2

Since nth term Tn = ar^n-1

Substituting the value of a and r into the equation will give;

Tn = 2(-4)^n-1

2(-4^n × -4^-1)

2(-4^n × -1/4)

= -4^n/2

zhenek [66]4 years ago
5 0

Answer:

32

Step-by-step explanation:

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\huge\text{Hey there!}

\mathsf{-\dfrac{c}{2}+43=50}

\large\text{SUBTRACT 43 to BOTH SIDES}

\mathsf{-\dfrac{c}{2}+43-43=50-43}

\large\textsf{CANCEL out: 43 - 43 because that gives you 0}

\large\textsf{KEEP: 50 - 43 because it helps solve for the c-value}

\mathsf{50 - 43 = \bf 7}

\large\text{NEW EQUATION: }\mathsf{-\dfrac{c}{2}=7}

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\mathsf{\dfrac{2}{-1}\times-\dfrac{c}{2}= \dfrac{2}{-1}\times7}

\large\textsf{CANCEL out: your RIGHT SIDE of the equation because that gives}\\\large\textsf{you 1}

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\uparrow\large\text{SIMPLIFY THE EQUATION ABOVE \& YOU HAVE YOUR}\\\large\text{C-VALUE}\uparrow

\boxed{\boxed{\large\text{ANSWER: \huge\bf  c = -14}}}\huge\checkmark

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~\frak{Amphitrite1040:)}

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