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Tcecarenko [31]
3 years ago
11

Write two polynomials with a difference of 2x2 + x + 3

Mathematics
1 answer:
Anettt [7]3 years ago
5 0

Answer:

The two polynomial CAN be 5x^4+5x^3+8x^2+x+6 and 5x^4+5x^3+8x^2+2x+13.

Step-by-step explanation:

Step 1: <u>Simplify the expression:</u>

2*2 + x + 3

4+x+3

x+7

Step 2: <u>Think of a random polynomial:</u>

5x^4+5x^3+8x^2+x+6

Step 3: <u>Either add your "random polynomial" by </u>x+7<u> or subtract it.</u>

<u>I want to add it so...</u>

5x^4+5x^3+8x^2+x+6+x+7

= 5x^4+5x^3+8x^2+2x+13

 Check by subtracting  5x^4+5x^3+8x^2+x+6 and 5x^4+5x^3+8x^2+2x+13.

         5x^4+5x^3+8x^2+2x+13

   -      5x^4+5x^3+8x^2+x+6

        _____________________

         0x^4 - 0x^3 -0x^2 +x +7 <em><u>or  </u></em>x+7<em><u /></em>

         

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Based on the data given in the picture, calculate the area of the car track...
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Refer to the diagram below. We need to find the areas of the green and blue regions, then subtract to get the area of the orange track only.

The larger green region is composed of a rectangle of dimensions 200 meters by 4+42+4 = 50 meters, along with two semicircles that combine to make a full circle. This circle has radius 25 meters.

The green rectangle has area 200*50 = 10000 square meters. The green semicircles combine to form an area of pi*r^2 = pi*25^2 = 625pi square meters. In total, the full green area is 10000+625pi square meters. I'm leaving things in terms of pi for now. The approximation will come later.

The blue area is the same story, but smaller dimensions. The blue rectangle has dimensions 200 meters by 42 meters, so its area is 200*42 = 8400 square meters. The blue semicircular pieces combine to a circle with area pi*r^2 = pi*21^2 = 441pi square meters. In total, the blue region has area 8400+441pi square meters.

After we figure out the green and blue areas, we subtract to get the orange region's area, which is the area of the track only.

orange area = (green) - (blue)

track area = (10000+625pi) - (8400+441pi)

track area = 10000+625pi - 8400-441pi

track area = (10000-8400) + (625pi - 441pi)

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4 0
3 years ago
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