Answer:
(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)
Step-by-step explanation:
we have
----> equation A
-----> equation B
solve by substitution
substitute equation B in equation A
solve for x
<em>Find the value of y</em>
For ---->
For ---->
therefore
The solutions are
(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)
Answer:
-6, -4, -3, -2, -1, 1, 2, 3, 4, 6
Step-by-step explanation:
The general formula for a fourth-degree polynomial is
f(x) = ax⁴ + bx³ + cx² + dx + e
Your polynomial is
f(x) = x⁴ - 9x² - 4x + 12
a = 1; e = 12
According to the Rational Roots Theorem, the possible rational roots are the factors of e divided by the factors of a.
Factors of e = ±1, ±2, ±3, ±4, ±6
Factors of a = ±1
Potential roots are x = ±1 ±2, ±3, ±4 ± 6
Putting them in order, we get the potential roots
x = -6, -4, -3, -2, -1, 1, 2, 3, 4, 6
(The graph of your function shows roots at x = -2, x = 1, and x = 3.)
