Answer: multiple choice?
Step-by-step explanation:
If I'm reading your equations correctly, they are:f(x)=x2-8x+15g(x)=x-3h(x)=f(x)/g(x)The domain of a function is the set of all possible inputs, what we can plug in for our variable.The largest two limitations on domains (other than explicit limitations, like in piecewise functions) are radicals and rational functions. With radical expressions we know that we CANNOT take an even root of a negative number. I don't see that problem here. With rationals we know that we CANNOT divide by zero. So the question becomes, when does h(x) ask us to divide by zero? When is the denominator of h(x) zero?Since the denominator of h(x) is g(x), we cannot let g(x) equal zero. So when does that happen? when x-3=0 or when x=3. I hope you see here that if x=3, then g(x)=0, and so h(x)=f(x)/0, which we CANNOT do. The domain of h(x) is all real numbers not equal to 3. There is more going on here. If you had factored f(x) first, you could have written h(x) in a confusing way:h(x)=( f(x) ) / ( g(x) )h(x)= ( (x-5)(x-3) ) / (x-3) Right here, it looks like (x-3) will cancel out from the top and bottom of your fraction. It does, in a way. The graph of h(x) will behave exactly like the line y=x-5, except that it has a hole in it at x=3 (check this! it's cool!)SOOO, the takeaway is that it is better to determine limitations on your domain BEFORE over-simplifying your equations.
Answer:
Step-by-step explanation:
We can create equivalent ratios by multiplying or dividing both the numerator and denominator of a given ratio by the same number
You can also write ratios 3 different ways:
____ to ____
____ : ____
___/___
Option C
The radius of circle is 13 units
<em><u>Solution:</u></em>
<em><u>The equation of circle is given by formula:</u></em>
Where, the center being at the point (h, k) and the radius being "r"
<em><u>Given that circle has its center at the origin</u></em>
(h, k) = (0, 0)
<em><u>(5, -12) is a point on the circle</u></em>
(x, y) = (5, 12)
<em><u>Substituting in equation we get,</u></em>
Thus radius of circle is 13 units
The absolute value of a number <em>a</em> is written as |a| . And represents the distance between a and 0 on a number line.
So, Option C. x≥ 11 or x ≤ 1 is correct answer
Inequality given is,
|x − 6| ≥ 5
Taking <em>positive case,</em>
x − 6 ≥ 5
x − 6 + 6 ≥ 5 + 6
x ≥ 11
Taking <em>negative case,</em>
x − 6 ≤ - 5
x - 6 + 6 ≤ -5 + 6
x ≤ 1
So, solution of given inequality is x ≥ 11 or x ≤ 1
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