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Jlenok [28]
3 years ago
8

Look at pic above to awnser the question

Mathematics
2 answers:
MissTica3 years ago
6 0
Mode- 16 and 5
Median-15
Range- 17
Median-11
alukav5142 [94]3 years ago
4 0
Mode 5 and 16, mean 11, median 14, range 17
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Help 2,4+0,8=.......-0,06=........+1,21=.......+1,78=....-5,14=.
horrorfan [7]
Lets write this out:-

2.4 + 0.8 =______ - 0.06 = _____+ 1.21=_____+1.78=_____- 5.14=___

So to solve d blanks we will do d following:-

2.4 + 0.8 = 3.2

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 - 0.06 = _____+ 1.21=_____+1.78=_____- 5.14=___

Now lets solve again:-

3.2 - 0.06 = 3.14 

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21=_____+1.78=_____- 5.14=___

Now lets solve again:-

3.14 + 1.21= 4.25

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78=_____- 5.14=___

Now lets solve again:-

4.25 +1.78= 6.03

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14=___

Now lets solve again:-

6.03 - 5.14 = 0.89

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14= 0.89

So, 2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14= 0.89

Hope I helped ya!! xD 
3 0
3 years ago
on january 1,1999,the price of gasoline was$1.39 per gallon .if the price of gasoline increased by 0.5%per month ,what was the w
arlik [135]
P(t)=1.39.(1.005)^t \ \ \ \ where t \ is \ time \ in \ months\\
\\
P(1)=1.39.(1.005)^1\\
\\
P(1)=1.39*1.005\\
\\
P(1)=\$ \ 1.40
4 0
3 years ago
Pleaseeee helpppp meee
Doss [256]

Answer:

try searching it

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What must be true of two rational expressions before they can be added?
cricket20 [7]
They must have common denominators
8 0
3 years ago
Read 2 more answers
Solve the compound inequality. 6 – x > 15 or 2x – 9 ≥ 3 A. x > 9 or x ≤ 6 B. x < 9 or x ≥ –6 C. x > –9 or x ≤ –6 D.
Vesnalui [34]

Answer:

Step-by-step explanation:

Solve the compound inequality. 6 – x > 15 or 2x – 9 ≥ 3 A. x > 9 or x ≤ 6 B. x < 9 or x ≥ –6 C. x > –9 or x ≤ –6 D. x < –9 or x ≥ 6

4 0
3 years ago
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