Answer:
range=u ± 3.09 sd
Step-by-step explanation:
Given:
mean, u= 26.8 mpg
standard deviation, sd=72 mpg
% contained in interval = 99.8%
the interval for 99.8% of the values of a normal distribution is given by
mean ± 3.09 standard deviation= u ± 3.09 sd
=26.8 ± 3.09(72)
=26.8 ± 222.48
= 249.28 , -195.68
range=u ± 3.09 sd = 249.28 , -195.68 !
Median is a better measure of center than the mean(average)
a) 56,62,68,71,104,507 ⇒ Median is a better measure. Mean is not a better measure because of the outliers.
b) 2,8.5, 9.2, 9.8, 10.1 lb ⇒ Median is a better measure.
c) Mean is a better measure. No outliers. Data set values are close with each other.
d) Mean is a better measure.
Answer:
21/20 (1 1/20)
Step-by-step explanation:
The answer would be 23 mL
36 because the rest are prime #'8
