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svetlana [45]
3 years ago
8

A dance competition on television had five elimination rounds. After each elimination, only one-fourth of the contestants were s

ent to the next round. The table below shows the number of contestants in each round of the competition: x 1 2 3 4 5 f(x) 512 128 32 8 2 Compute the average rate of change of f(x) from x = 2 to x = 4 and describe what it represents.
−60 contestants per round, and it represents the average rate at which the number of contestants changed from the second round to the fourth round

−120 contestants per round, and it represents the average rate at which the number of contestants changed from the second round to the fourth round

−60 contestants per round, and it represents the number of contestants who will reach the final round

−120 contestants per round, and it represents the number of contestants who will reach the final round
Mathematics
2 answers:
ella [17]3 years ago
6 0

Answer:

A

Step-by-step explanation:

creativ13 [48]3 years ago
4 0
When x =2, f(x) = 128
When x = 4, f(x) = 8

The changing rate is \frac{8-128}{4-2}= \frac{-120}{2}=-60

This changing rate represents the decrease of the number of contestants as the competition approaches the final.

Correct option is the first option
<span>
−60 contestants per round and it represents the average rate at which the number of contestants changed from the second round to the fourth round 
</span>
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The Jones family traveled 314 miles each day until they reached their destination, which is 1,256 miles away from their starting
skelet666 [1.2K]
1256/314= 4 days until arrival
8 0
3 years ago
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Earnie borrowed 3,000 from the bank. The interest is $4 for every 100 he borrowed. How much money must Ernie repay the bank for
Alecsey [184]

Answer:

$120

Step-by-step explanation:

100x30=3000

4x30=120

4 0
3 years ago
In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini
svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2

The augmented matrix is

\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]

The reduction of this matrix to row-echelon form is outlined below.

R_2\rightarrow R_2-R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]

R_3\rightarrow R_3-2R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]

R_3\rightarrow R_3-R_2

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]

The last row determines, if there are solutions or not. To be consistent, we must have k such that

k^2-k-2=0

\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2

Case k = −1:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]

This gives the infinite many solution.

5 0
3 years ago
2X- 10 =30 solve for X
Kazeer [188]
2x - 10 = 30
2x = 40
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5 0
3 years ago
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Find the slope of the<br> line through the<br> points (1,-2) and (-7,4)
horrorfan [7]

Answer:

-3/4

Step-by-step explanation:

To find the slope, plug the coordinates into the slope formula.

y2 - y1 / x2 - x1

4 - (-2) / -7 - 1

6 / - 8

-3/4

6 0
3 years ago
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