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svetlana [45]
3 years ago
8

A dance competition on television had five elimination rounds. After each elimination, only one-fourth of the contestants were s

ent to the next round. The table below shows the number of contestants in each round of the competition: x 1 2 3 4 5 f(x) 512 128 32 8 2 Compute the average rate of change of f(x) from x = 2 to x = 4 and describe what it represents.
−60 contestants per round, and it represents the average rate at which the number of contestants changed from the second round to the fourth round

−120 contestants per round, and it represents the average rate at which the number of contestants changed from the second round to the fourth round

−60 contestants per round, and it represents the number of contestants who will reach the final round

−120 contestants per round, and it represents the number of contestants who will reach the final round
Mathematics
2 answers:
ella [17]3 years ago
6 0

Answer:

A

Step-by-step explanation:

creativ13 [48]3 years ago
4 0
When x =2, f(x) = 128
When x = 4, f(x) = 8

The changing rate is \frac{8-128}{4-2}= \frac{-120}{2}=-60

This changing rate represents the decrease of the number of contestants as the competition approaches the final.

Correct option is the first option
<span>
−60 contestants per round and it represents the average rate at which the number of contestants changed from the second round to the fourth round 
</span>
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Given that X ~ N(120, 35). We survey samples of 25 and are interested in the distribution of X-bar. Find the z-score associated
lubasha [3.4K]

Answer:

Option c -2.8571

Step-by-step explanation:

z-score are calculated as

z=\frac{xbar-mean}{\frac{S.D}{\sqrt{n} } }.

We are given that mean=120 and standard deviation=S.D=35 as X~N(120,35).

Sample size=n=25.

We have to find z-score for x-bar=100. So,

z-score=[100-120]/[35/√25]

z-score=[-20]/[35/5]

z-score=-20/7

z-score=-2.8571.

Thus,  the z-score associated with x-bar = 100 is -2.8571.

8 0
3 years ago
What metric unit would you use to measure the length of a football field?
Sati [7]
Meters, yards are not in the metric system

3 0
3 years ago
I am having trouble with this relative minimum of this equation.<br>​
Norma-Jean [14]

Answer:

So the approximate relative minimum is (0.4,-58.5).

Step-by-step explanation:

Ok this is a calculus approach.  You have to let me know if you want this done another way.

Here are some rules I'm going to use:

(f+g)'=f'+g'       (Sum rule)

(cf)'=c(f)'          (Constant multiple rule)

(x^n)'=nx^{n-1} (Power rule)

(c)'=0               (Constant rule)

(x)'=1                (Slope of y=x is 1)

y=4x^3+13x^2-12x-56

y'=(4x^3+13x^2-12x-56)'

y'=(4x^3)'+(13x^2)'-(12x)'-(56)'

y'=4(x^3)'+13(x^2)'-12(x)'-0

y'=4(3x^2)+13(2x^1)-12(1)

y'=12x^2+26x-12

Now we set y' equal to 0 and solve for the critical numbers.

12x^2+26x-12=0

Divide both sides by 2:

6x^2+13x-6=0

Compaer 6x^2+13x-6=0 to ax^2+bx+c=0 to determine the values for a=6,b=13,c=-6.

a=6

b=13

c=-6

We are going to use the quadratic formula to solve for our critical numbers, x.

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

x=\frac{-13 \pm \sqrt{13^2-4(6)(-6)}}{2(6)}

x=\frac{-13 \pm \sqrt{169+144}}{12}

x=\frac{-13 \pm \sqrt{313}}{12}

Let's separate the choices:

x=\frac{-13+\sqrt{313}}{12} \text{ or } \frac{-13-\sqrt{313}}{12}

Let's approximate both of these:

x=0.3909838 \text{ or } -2.5576505.

This is a cubic function with leading coefficient 4 and 4 is positive so we know the left and right behavior of the function. The left hand side goes to negative infinity while the right hand side goes to positive infinity. So the maximum is going to occur at the earlier x while the minimum will occur at the later x.

The relative maximum is at approximately -2.5576505.

So the relative minimum is at approximate 0.3909838.

We could also verify this with more calculus of course.

Let's find the second derivative.

f(x)=4x^3+13x^2-12x-56

f'(x)=12x^2+26x-12

f''(x)=24x+26

So if f''(a) is positive then we have a minimum at x=a.

If f''(a) is negative then we have a maximum at x=a.

Rounding to nearest tenths here:  x=-2.6 and x=.4

Let's see what f'' gives us at both of these x's.

24(-2.6)+25

-37.5  

So we have a maximum at x=-2.6.

24(.4)+25

9.6+25

34.6

So we have a minimum at x=.4.

Now let's find the corresponding y-value for our relative minimum point since that would complete your question.

We are going to use the equation that relates x and y.

I'm going to use 0.3909838 instead of .4 just so we can be closer to the correct y value.

y=4(0.3909838)^3+13(0.3909838)^2-12(0.3909838)-56

I'm shoving this into a calculator:

y=-58.4654411

So the approximate relative minimum is (0.4,-58.5).

If you graph y=4x^3+13x^2-12x-56 you should see the graph taking a dip at this point.

3 0
3 years ago
Natalie just rented an apartment for $900 a month. She was told that the rent will increase 5.5% each year. About how much will
belka [17]
$1246. 

<span>This is a guess, though.</span>
6 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=0.6%20%5Csqrt%7B33.54%7D%20" id="TexFormula1" title="0.6 \sqrt{33.54} " alt="0.6 \sqrt{33.54}
ki77a [65]

0.6\sqrt{33.54}

=5.79137

0.6*5.79137

=3.4

Hope this helps!

Thanks!

-Charlie

6 0
3 years ago
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