7 = b/11
11 × 7 = 77
Answer:
b = 7
Minus 5 from both sides so we have 3a=-19 now divide both sides by 3 so we have a=-6 1/3
Answer:
(-∞, -12), (2, ∞)
or
(-∞, -12) U (2, ∞)
Step-by-step explanation:
|3x + 15| > 21, |3x + 15| < -21
3x + 15 > 21, 3x + 15 < - 21
-15 -15 -15 -15
------------------ -------------------
3x > 6 3x < - 36
÷3 ÷3 ÷3 ÷3
------------ ------------------
x > 2 x < -12
(-∞, -12), (2, ∞)
or
(-∞, -12) U (2, ∞)
I hope this helps!

is a complex number that satisfies
![\begin{cases}r\cos x=-3\\[1ex]r\sin x=4\\[1ex]r=\sqrt{(-3)^2+4^2}\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7Dr%5Ccos%20x%3D-3%5C%5C%5B1ex%5Dr%5Csin%20x%3D4%5C%5C%5B1ex%5Dr%3D%5Csqrt%7B%28-3%29%5E2%2B4%5E2%7D%5Cend%7Bcases%7D)
The last equation immediately tells you that

.
So you have
![\begin{cases}\cos x=-\dfrac35\\[1ex]\sin x=\dfrac45\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D%5Ccos%20x%3D-%5Cdfrac35%5C%5C%5B1ex%5D%5Csin%20x%3D%5Cdfrac45%5Cend%7Bcases%7D)
Dividing the second equation by the first, you end up with

Because the argument's cosine is negative and its sine is positive, you know that

. This is important to know because it's only the case that

whenever

. The inverse doesn't exist otherwise.
However, you can restrict the domain of the tangent function so that an inverse can be defined. By shifting the argument of tangent by

, we have

All this to say

So,

.