<span>The contradiction term for "at most one obtuse angle" is "no obtuse angles
so therefore i conclude that the </span> statement she will most likely use as an assumption is
Let each angle of a triangle be acute
so option A is correct
hope it helps
Answer:
(7, 24, 26)
Step-by-step explanation:
A Pythagorean triple must have an odd number of even numbers. The triple (7, 24, 26) is not a Pythagorean triple.
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<em>Additional comment</em>
For an odd integer n, a triple can be formed as ...
(n, (n²-1)/2, (n²+1)/2)
That is, the following will be Pythagorean triples.
- (3, 4, 5)
- (5, 12, 13)
- (7, 24, 25)
- (9, 40, 41)
- (11, 60, 61)
Another series involves even numbers and numbers separated by 2:
(2n, n²-1, n²+1)
- (8, 15, 17)
- (12, 35, 37)
- (16, 63, 65)
In this list, if n is not a multiple of 2, the triple will be a multiple of one from the odd-number series.
It is a good idea to remember a few of these, as they tend to show up in Algebra, Geometry, and Trigonometry problems.
Answer:
B
Step-by-step explanation:
The answer is B I just had this question
Answer:
it would be 3/7
Step-by-step explanation:
3+4=7 3 cousins out of the seven are girls
Twelve people join hands for a circle dance.In how many ways can they do this? Suppose six of these people are men, and the other six are women. In how many ways can they join hands for a circle dance, assuming they alternate in gender around the circle
Answer:
86400 ways
Step-by-step explanation:
Since the circle can be rotated, the number of ways to arrange a distinct number of n objects in a circle will be (n−1)!.
Now, if we rotate the circle with the six women, we will see that there are 5! ways with which they can be placed in the circle.
After picking the places for the women, we will now fill each gap between two women with a man.
We have 6 men. Thus, number of ways to arrange the men is 6!
Thus,number of ways they can join hands for a circle dance, assuming they alternate in gender around the circle = 5! × 6! = 86400 ways
