Answer:
1.) 48
2.) 65
3.) 36
Step-by-step explanation:
1.) If the equation is 6(x-4) and x = 12, then all we have to do is plug in the value of x. When we plug in, all we do is substitute 12 for x because they mentioned in the question that x = 12. So, we end up getting 6(12 - 4). After solving this, we get 48.
2.) This problem is a lot like the last problem. All we need to do is substitute /plug in the values of x and y into the equation, to get 4(4^2) - 35/7 - (8 + 14). After solving, we get 65.
3.) . This problem, once again, is also a lot like the last problems. We need to substitute the value of x into the equation 8x+12. Since we know from the problem that x is 3, all we have to do is 8 * 3 + 12.
<u>ANSWER</u>
A. (4,12)
<u>EXPLANATION</u>
The equations are:

and

To eliminate a variable we make the coefficients of that variable the same in both equations.
It is easier to eliminate x.
We multiply the first equation by 2 to get:

We add equations (2) and (3).


Divide both sides by 23


Put x=4 into equation (1).






The solution is (4,12)
Answer:
506
Step-by-step explanation:
do the math

Break the expression into group:

factor out x from 4x² - 5x : x (4x-5)
factor out 3 from 12x-15 : 3 (4x-5)

factor out common term (4x-5) :

hope this helps!
Answer:
a) p + q + r
b) 2(a + b)
Step-by-step explanation:
The perimeter of a two-dimensional shape is the <u>distance</u> all the way around the outside.
An algebraic expression contains one or more numbers, variables, and arithmetic operations.
A variable is a symbol (usually a letter) that represents an unknown numerical value in an equation or expression.
<u>Question (a)</u>
The length of each side of the triangle is labeled p, q and r. Therefore, the perimeter is the sum of the sides:
Perimeter = p + q + r
So the algebraic expression for the perimeter of the triangle is:
p + q + r
<u>Question (b)</u>
Not all of the sides of the shape have been labeled.
However, note that the horizontal length labeled "a" is equal to the sum of "c" and the horizontal length with no label.
Similarly, note that the vertical length labeled "b" is equal to the sum of "d" and the vertical length with no label.
Therefore, the perimeter is twice the sum of a and b:
Perimeter = 2(a + b)
So the algebraic expression for the perimeter of the shape is:
2(a + b)