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3 years ago

12

Please answer question ASAP!!!! Points I will give:25

1 answer:

lana66690 [7]3 years ago

3 0

I say the answer would be H. 52.335seconds

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Simplify the expression: 2[12-3(4+2)]

Vinil7 [7]

$2(12 - 3(6))$
$2(9(6))$
$2(54)$
$108$
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4 0

3 years ago

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PLEASE HELP AND SHOW WORK i'm very confused

noname [10]

Answer:

a. about 15.51 miles, rounded to 15.5 miles

b. about 31.02 miles, rounded to 31 miles

Step-by-step explanation:

Sunday Monday Tuesday Wednesday Thursday Friday Saturday

10 20 40 80 160 320 640

1280 2560 5120 10240 20480 40960 81920

81920/5280 = 15.51515151, rounded to the nearest tenth of a mile, 15.5 miles

Question b asks for how many miles in total has he ran. That means we have to add each of the values shown above and that equals to 163830 feet.

Divide that by 5280 and that equals 31.02 miles, rounded to the nearest tenth, 31 miles.

4 0

3 years ago

Evaluate the expression. 1/2 x (4+8)

Elanso [62]

Answer:

Hey there!

1/2 x (4+8)

1/2 x (12)

6

Hope this helps :)

8 0

3 years ago

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Help me I need the math problem

miss Akunina [59]

Answer:

y=4x-3

Step-by-step explanation:

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2 years ago

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A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by ℎ = −16푡 ଶ+103푡+5 w

Liono4ka [1.6K]

Question:

A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by h(t)=-16t^2+80t+5, where t is measured in seconds. Write an equation to determine how long it will take for the ball to reach the ground.

Answer:

$t = 5.0625$

Step-by-step explanation:

Given

$h(t)=-16t^2+80t+5$

Required

Find t when the ball hits the ground

This implies that h(t) = 0

So, we have:

$0=-16t^2+80t+5$

Reorder

$-16t^2+80t+5 = 0$

Using quadratic formula, we have:

$t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}$

Where

$a = -16$ $b =80$ $c = 5$

So, we have:

$t = \frac{-80\±\sqrt{80^2 - 4*-16*5}}{2*-16}$

$t = \frac{-80\±\sqrt{6400 +320}}{-32}$

$t = \frac{-80\±\sqrt{6720}}{-32}$

$t = \frac{-80\±82.0}{-32}$

This gives:

$t = \frac{-80+82.0}{-32}$ or $t = \frac{-80-82.0}{-32}$

$t = \frac{2}{-32}$ or $t = \frac{-162}{-32}$

$t = -\frac{2}{32}$ or $t = \frac{162}{32}$

But time can not be negative.

So, we have:

$t = \frac{162}{32}$

$t = 5.0625$

<em>Hence, time to hit the ground is 5.0625 seconds</em>

3 0

3 years ago