Answer:
9,103.69
Step-by-step explanation:
y = A(d)^x
y = 12000(1-0.129)^2
Decay y = 12000(0.871)^2
solve for y = $ 9,103.69
To solve this we are going to use the exponential function:
![f(t)=a(1(+/-)b)^t](https://tex.z-dn.net/?f=f%28t%29%3Da%281%28%2B%2F-%29b%29%5Et)
where
![f(t)](https://tex.z-dn.net/?f=f%28t%29)
is the final amount after
![t](https://tex.z-dn.net/?f=t)
years
![a](https://tex.z-dn.net/?f=a)
is the initial amount
![b](https://tex.z-dn.net/?f=b)
is the decay or grow rate rate in decimal form
![t](https://tex.z-dn.net/?f=t)
is the time in years
Expression A
![f(t)=624(0.95)^{4t}](https://tex.z-dn.net/?f=f%28t%29%3D624%280.95%29%5E%7B4t%7D)
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate
![b](https://tex.z-dn.net/?f=b)
, we are going to use the formula:
![b=|1-base|](https://tex.z-dn.net/?f=b%3D%7C1-base%7C)
*100%
![b=|1-0.95|](https://tex.z-dn.net/?f=b%3D%7C1-0.95%7C)
*100%
![b=0.05](https://tex.z-dn.net/?f=b%3D0.05)
*100%
![b=](https://tex.z-dn.net/?f=b%3D)
5%
We can conclude that expression A decays at a rate of 5% every three months.
Now, to find the initial value of the function, we are going to evaluate the function at
![t=0](https://tex.z-dn.net/?f=t%3D0)
![f(t)=624(0.95)^{4t}](https://tex.z-dn.net/?f=f%28t%29%3D624%280.95%29%5E%7B4t%7D)
![f(0)=624(0.95)^{0t}](https://tex.z-dn.net/?f=f%280%29%3D624%280.95%29%5E%7B0t%7D)
![f(0)=624(0.95)^{0}](https://tex.z-dn.net/?f=f%280%29%3D624%280.95%29%5E%7B0%7D)
![f(0)=624(1)](https://tex.z-dn.net/?f=f%280%29%3D624%281%29)
![f(0)=624](https://tex.z-dn.net/?f=f%280%29%3D624)
We can conclude that the initial value of expression A is 624.
Expression B
![f(t)=725(1.12)^{3t}](https://tex.z-dn.net/?f=f%28t%29%3D725%281.12%29%5E%7B3t%7D)
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
![b=|1-base|](https://tex.z-dn.net/?f=b%3D%7C1-base%7C)
*100%
![b=|1-1.12|](https://tex.z-dn.net/?f=b%3D%7C1-1.12%7C)
*100
![b=|-0.12|](https://tex.z-dn.net/?f=b%3D%7C-0.12%7C)
*100%
![b=0.12](https://tex.z-dn.net/?f=b%3D0.12)
*100%
![b=](https://tex.z-dn.net/?f=b%3D)
12%
We can conclude that expression B grows at a rate of 12% every 4 months.
Just like before, to find the initial value of the expression, we are going to evaluate it at
![t=0](https://tex.z-dn.net/?f=t%3D0)
![f(t)=725(1.12)^{3t}](https://tex.z-dn.net/?f=f%28t%29%3D725%281.12%29%5E%7B3t%7D)
![f(0)=725(1.12)^{0t}](https://tex.z-dn.net/?f=f%280%29%3D725%281.12%29%5E%7B0t%7D)
![f(0)=725(1.12)^{0}](https://tex.z-dn.net/?f=f%280%29%3D725%281.12%29%5E%7B0%7D)
![f(0)=725(1)](https://tex.z-dn.net/?f=f%280%29%3D725%281%29)
![f(0)=725](https://tex.z-dn.net/?f=f%280%29%3D725)
The initial value of expression B is 725.
We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months.
- Expression A has an initial value of 624, while expression B has an initial value of 725.
Answer:
The bike costs $130.
Step-by-step explanation:
1) 200 x 0.35 = 70
2) 200 - 70 = 130
Answer:
25 mins
Step-by-step explanation:
Harpeet worked -- x mins
Aiysha worked -- 2x mins
If Aiysha worked 50 mins, Harpeet worked:
2x = 50
x = 25 mins
Thenks and mark me brainliest :))
You have to multiply 1/3 x 3/4= 3/12 = 1/4