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3 years ago

Find cotx if sinx cotx cscx = sqrt2

Mathematics

1 answer:

Misha Larkins [42]3 years ago

6 0

Answer:

$cot(x)=\sqrt2$

Step-by-step explanation:

$sin(x)cot(x)csc(x) = \sqrt2$ , csc(x) = 1/sin(x)

$sin(x)cot(x)(\frac{1}{sin(x)}) = \sqrt2$

$cot(x)=\sqrt2$

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A family of four goes to a salon for haircuts the cost of each haircut is $13 use distributive property to find the product 4*13

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3 years ago

Read 2 more answers

3. Solve the inequality –2(z + 5) + 20 > 6.

12345 [234]

$\boxed{-2\left(z+5\right)+20>6\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:z$

Solution:

Given inequality is:

$-2(z+5)+20>6$

We have to solve the given inequality

$-2\left(z+5\right)+20>6\\\\\mathrm{Subtract\:}20\mathrm{\:from\:both\:sides}\\\\-2\left(z+5\right)+20-20>6-20\\\\\mathrm{Simplify}\\\\-2\left(z+5\right)>-14$

$Multiply\ both\ sides\ by\ -1\ \left(reverse\:the\:inequality\right)$

Whenever we multiply or divide an inequality by a negative number, we must flip the inequality sign

$\left(-2\left(z+5\right)\right)\left(-1\right)$

Thus the solution to inequality is:

$-2\left(z+5\right)+20>6\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:z$

4 0

3 years ago

Find the equation of the line that goes through (-8,11) and is perpendicular to x= - 15. Write the equation in the form x = a, y

galben [10]

Answer:

y=11

Step-by-step explanation:

Hi there!

We want to find the equation of the line that passes through the point (-8, 11) and is perpendicular to x=-15

If a line is perpendicular to another line, it means that the slopes of those lines are negative and reciprocal; in other words, the product of the slopes is equal to -1

The line x=-15 has an undefined slope, which we can represent as 1/0, which is also undefined.

To find the slope of the line perpendicular to x=-15, we can use this equation (m is the slope):

$m_1*m_2=-1$

$m_1$ in this instance would be 1/0, so we can substitute it into the equation:

$\frac{1}{0} *m_2=-1$

Multiply both sides by 0

$m_2=0$

So the slope of the new line is 0

We can substitute it into the equation y=mx+b, where m is the slope and b is the y intercept:

y=0x+b

Now we need to find b:

Since the equation passes through the point (-8,11), we can use its values to solve for b.

Substitute -8 as x and 11 as y:

11=0(-8)+b

Multiply

11=0+b, or 11=b

So substitute into the equation:

y=0x+11

We can also write the equation as y=11

Hope this helps!

5 0

3 years ago

Evaluate the function for the given values to determine if the value is a root. p(−2) = p(2) = The value is a root of p(x).

bija089 [108]

Note: Since you missed to mention the the expression of the function $p(x)$ . After a little research, I was able to find the complete question. So, I am assuming the expression as $p(x)=x^4-9x^2-4x+12$ and will solve the question based on this assumption expression of $p(x)$ , which anyways would solve your query.

Answer:

$p\left(-2\right)=0$

Therefore, $x=-2$ is a root of the polynomial $p(x)=x^4-9x^2-4x+12$

$p\left(2\right)=-16$

Therefore, $x=2$ is not a root of the polynomial $p(x)=x^4-9x^2-4x+12$

Step-by-step explanation:

As we know that for any polynomial let say $p(x)$ , $c$ is the root of the polynomial if $p(c)=0$ .

In order to find which of the given values will be a root of the polynomial, $p(x)=x^4-9x^2-4x+12$ , we must have to evaluate $p(x)$ for each of these values to determine if the output of the function gets zero.

So,

Solving for $p\left(-2\right)$