Can someone please help me with this please i forgot how to do it
1 answer:
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Answer:
Step-by-step explanation:
ax² + bx + c = a(x - )(x -
)
D = b² - 4ac
= ( - b ± √D ) / 2a
~~~~~~~~~~~~
Let x² = y , then y² + 8y - 9
Find the roots of equation y² + 8y - 9 = 0
D = 64 + 36 = 100 = 10²
= ( - 8 - 10) / 2 = - 9
= ( - 8 + 10) / 2 = 1
y² + 8y - 9 = (y - 1)(y + 9) = (x² - 1)(x² + 9)
x² = 1 ⇒ = ± √1
+ 8x² - 9 = (x - 1)(x + 1)(x² + 9)
