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kati45 [8]
2 years ago
5

Prove that 1/sin^2A -1/tan^2A= 1

Mathematics
1 answer:
Vika [28.1K]2 years ago
4 0

Answer:

Step-by-step explanation:

LHS =\dfrac{1}{Sin^{2} \ A }-\dfrac{1}{Tan^{2} \ A }\\\\\\ = \dfrac{1}{sin^{2} \ A}- \dfrac{1}{\dfrac{Sin^{2} \ A}{Cos^{2} \ A}}\\\\\\= \dfrac{1}{sin^{2} \ A } - \dfrac{Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{1-Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{Sin^{2} \ A}{Sin^{2} \ A}\\\\\\= 1 = \ RHS

Hint: 1 - Cos² A = Sin² A

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Answer:

The time required to finish the work by both candy and Tim working together = 36.83 minute

Step-by-step explanation:

Time taken by the candy to finish the work T_{1}= 85 min

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Thus the time taken by both to finish the work = \frac{T_1 \times\ T_2}{T_1 + T_2}

Put the values of T_{1} and T_{2}  we get ,

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2 years ago
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