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3 years ago

The following table shows the distance from Tessa's house to her favorite locations.

Mathematics

1 answer:

777dan777 [17]3 years ago

3 0

About 55km not sure tho

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1161.90 to the nearest hundred

forsale [732]

1 thousand
1 hundred---- need to round up
6 tens
1 ones
Would be rounded up to 1200
Hope this helps

8 0

3 years ago

WILL MARK BRAINLIEST A sample of 64 was taken from a population, with the mean of the sample being 119 and the standard deviatio

Anettt [7]

Answer:

B. 117, 121

Step-by-step explanation:

6 0

3 years ago

Find the Missing length indicated

Diano4ka-milaya [45]

Answer:

dhjdhshsbdbdhhdhehthfixudhdjfbhf

ooopsss my baby sissy

7 0

3 years ago

What is the volume of the shape?

rodikova [14]

Answer:

volume: 1/3 a²h

= 1/3 ×2²x6

= 8 feet³

6 0

3 years ago

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 98% confidence interval for the population mean, $\mu$ is;

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0

3 years ago