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Wewaii [24]
3 years ago
12

The number 0 belongs to which classification?

Mathematics
2 answers:
AysviL [449]3 years ago
8 0
The answer is C. Integers
Vinil7 [7]3 years ago
7 0
Your answer will be C. Integers
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alukav5142 [94]
3 4/10 is my answer



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3 0
3 years ago
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Solve 11 ≤ w + 3.4 i dont know the answer please help me
shepuryov [24]

Answer:

7.6 ≤w

Step-by-step explanation:

Hey there!

In order to solve this inequality, you need to simplify the inequality like the following:

Subtract 3.4 from both sides

7.6 ≤w

This means that w is greater than or equal to 7.6

6 0
2 years ago
Evaluate the integral. 3 2 t3i t t − 2 j t sin(πt)k dt
sveta [45]

∫(t = 2 to 3) t^3 dt

= (1/4)t^4 {for t = 2 to 3}

= 65/4.

----

∫(t = 2 to 3) t √(t - 2) dt

= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2

= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du

= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}

= 26/15.

----

For the k-entry, use integration by parts with

u = t, dv = sin(πt) dt

du = 1 dt, v = (-1/π) cos(πt).


So, ∫(t = 2 to 3) t sin(πt) dt

= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt

= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]

= 5/π + 0

= 5/π.

Therefore,

∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.

3 0
3 years ago
What is the equation of the line????????
IrinaVladis [17]

Answer:

y=1/2x+2

Step-by-step explanation:

The equations come in the form of y=mx+c, where m is the gradient and c is the y-intercept. Looking at the graph we know that the y-intercept is (0,2), so that rules out options B and C.

To find the gradient is a little more tricky, but we can follow the formula:

\frac{rise}{run}, where rise is the vertical value and run is the horizontal value

So we sub in our values:

\frac{2}{4}

And simplify:

\frac{1}{2}

So now we sub in our new found values into y=mx+c:

y=1/2x+2

8 0
2 years ago
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PLZ ANSWER ILL GIVE BRAINILEST2 box plots. The number line goes from 26 to 36. For Pleasantville Middle School, the whiskers ran
Svetach [21]

Answer:

I believe the answer is- The mean and MAD can accurately describe the "typical" value in the symmetric data set.

Step-by-step explanation:

The other answers don't make sense because the mean and MAD are being used for symmetrical distributions and asymmetrical means uneven distributions.

6 0
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