Answer:
2.84
Step-by-step explanation:
20.00 - 17.16 : If you think of it with zeros it might help
2.84 when solved
Micheal has 40ft of fencing for the rectangular dog run. So the perimeter of the dog run is 40ft.
Perimeter=40ft
The perimeter of a rectangle is:
P=2l+2w
Since we know the length is 5 and the perimeter is 40, we can solve for the width.
P=2l+2w
40=2*(5)+2w
40=10+2w
subtract 10 from both sides
30=2w
divide both sides by 2
15=w
The width of the fence is 15feet.
To determine the answer of Part A draw the equilateral triangle and the to determine the coordinates of of the third charge use that triangle.
To calculate the gravitational field strength in part B from each of the charges use the following equation.
E=kcq/r2
If you would add those values then you can use the symmetry about the y axis to make the vector addition a litter easier.<span />
Answer:
Step-by-step explanation:
Without a second equation relating x and y, we can solve 3x - 1/2y = 2 ONLY for x in terms of y or for y in terms of x:
x in terms of y: Multiply all three terms of 3x - 1/2y = 2 by 2, to eliminate the fraction: 6x - y = 4. Now add y to both sides to isolate 6x: 6x = 4 + y.
Last, divide both sides by 6 to isolate x:
x = (4 + y)/6
y in terms of x:
y = 6x - 4
If you want a numerical solution, please provide another equation in x and y and solve the resulting system.
Answer:
x^2+8x+<u>1</u><u>6</u><u>=</u><u>(</u><u>x-4</u><u>)</u><u>^</u><u>2</u>
<em><u>EXPLANATION</u></em><em><u>:</u></em>
<u>(</u><u>a</u><u>+</u><u>b</u><u>)</u><u>^</u><u>2</u><u>=</u><u>a2</u><u>+</u><u>2</u><u>.</u><u>a</u><u>.</u><u>b</u><u>+</u><u>b2</u>
<u>we</u><u> </u><u>have</u><u> </u><u>to</u><u> </u><u>break</u><u> </u><u>the</u><u> </u><u>middle</u><u> </u><u>term</u><u> </u><u>i</u><u>n</u><u> </u><u>2</u><u>a</u><u>b</u><u> </u><u>here</u><u> </u><u>a</u><u> </u><u>is</u><u> </u><u>x</u><u> </u><u>then</u><u> </u><u>2</u><u>x</u><u>b</u><u>=</u><u>8</u><u>x</u><u>,</u><u> </u><u>=</u><u>></u><u> </u><u>b</u><u>=</u><u>4</u><u>,</u><u> </u><u>but</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>and</u><u> </u><u>b</u><u> </u><u>to</u><u> </u><u>get</u><u> </u><u>the</u><u> </u><u>req</u><u>uired</u><u> </u><u>equation</u><u>!</u>