Which Numbers or do you need help on all of them
Answer:
x = 5
Step-by-step explanation:
Ordinarily, one would not need the distributive property to solve this equation. It is quickly and easily solved by making use of the multiplication property of equality: multiply both sides of the equation by 1/3.
3x(1/3) = 15(1/3)
x = 5
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To use the <em>distributive property</em>, we need the sum of two terms that have a common factor. We can get that form by subtracting 15 from both sides of the equation (subtraction property of equality):
3x - 15 = 15 - 15 . . . . subtract 15
3x -15 = 0 . . . . . . . . .simplify
Now, we can apply the distributive property to remove a factor of 3:
3(x -5) = 0
And we can use the multiplication property of equality to multiply by 1/3:
3(1/3)(x -5) = 0(1/3)
x -5 = 0 . . . . . . . . . . simplify
Finally, we can add 5 to both sides of the equation (addition property of equality):
x -5 +5 = 0 +5
x + 0 = 5 . . . . . . simplify
x = 5 . . . . . . . . . .simplify more
Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Answer:
33.08 m
Step-by-step explanation:
angle of ∆ = 131.6 - 90 = 41.6
=> x² = 8²+3²-2(8)(3)cos 41.6°
= 64+9-48(0.75)
= 73 - 36
= 37
x = √37 = 6.08 m
perimeter = (3×8)+3+6.08 = 33.08 m
