Let's solve your system by elimination.
8x+y=−16;3x−y=5
8x+y=−16
3x−y=5
Add these equations to eliminate y:
11x=−11
Then solve: 11x=−11 for x:
11x=−11
11x
11
=
−11
11
(Divide both sides by 11)
x=−1
Now that we've found x let's plug it back in to solve for y.
Write down an original equation:
8x+y=−16
Substitute: −1 for x in 8x+y=−16:
(8)(−1)+y=−16
y−8=−16(Simplify both sides of the equation)
y−8+8=−16+8(Add 8 to both sides)
y=−8
Answer:
x=−1 and y=−8
17)
x² + 8 = -8
x² = -8 - 8
x² = 16
x = ±√-16
x = ±√16i
x = <span>±4i
</span>
18)
x² + 5 = -3
x² = -3 - 5
x² = -8
x = ±√-8
x = ±√8i
x = ±2√2i
19)
x² + 3 = 0
x² = -3
x = ±√-3
x = <span>±</span>√3i
hope this helps, God bless!
Answer:
B) 10
Step-by-step explanation:
∠IJA= ∠HJA
ΔIJA has twice smaller side opposite ∠J than ∠A
Similarly
ΔHLA side 5 opposite ∠J,
So x/5= 20/10 ⇒ x= 5*2= 10
Answer choice is B) 10