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lutik1710 [3]
3 years ago
9

The truck left for delivery at 7:15 a.m. and

Mathematics
1 answer:
Jlenok [28]3 years ago
5 0

Answer:

45+1/3 (all 1/3 is 1/3 of an hour, so do 60/3 to get 20) meaning that 45+20 is 65 minutes or an hour and 5 minutes

Step-by-step explanation:

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Can a number be a factor and a multiple of<br> itself?
valkas [14]

Answer:

Yes

Step-by-step explanation:

Example, the number 4:

Multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44

Factors of 4: 1, 2, 4

5 0
3 years ago
Read 2 more answers
Exponentiation is the raising of one number to the power of another. This operation is performed using two asterisks **. Let's u
Harlamova29_29 [7]

In math, Exponentiation refers to the operation of raising one quantity to the power of another. See the program running the exponentiation below.

<h3>What is the required code?</h3>

The code is given below:

number_of_days = 30

amount_after_30days = 0.01 * (2 ** number_of_days)

# print the amount

print(amount_after_30days)

Learn more about exponentiation at;
brainly.com/question/11975096
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4 0
2 years ago
What value of x <br> in the solution set of 2(3x – 1) ≥ 4x – 6?
Brrunno [24]
First, you must distribute 2(3x-1).
To do that, you will multiply 2•3x, and 2•-1 because you are taking the number outside of the parentheses and multiplying (distributing) it to all the numbers inside

After distributing, the left side of your inequality will be 6x-2

Now you have
6x - 2 \geqslant 4x - 6

To find the value of x, you must subtract an x value from both sides of the equation, as well as a constant from each side.

so you have
6x - 2 \geqslant 4x - 6 \\ - 6x \geqslant + 6
And that will make the equation
- 4 \geqslant - 2x
Now, divide the variable side, ***BUT, because you are dividing by a negative number in an inequality, the inequality will switch sides.

Then, the value of x is greater than or equal to 2
5 0
3 years ago
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Express the sum of (square root) -64 and 3(square root) -4 as a monomial in terms of I.
Inga [223]
\bf \sqrt{-64}~+~3\sqrt{-4}\implies \sqrt{-1\cdot 2^6}~+~3\sqrt{-1\cdot 2^2}&#10;\\\\\\&#10;\sqrt{-1}\cdot \sqrt{2^6}~+~3\sqrt{-1}\cdot \sqrt{2^2}\implies i\cdot \sqrt{2^{3\cdot 2}}~+~3\cdot i\cdot 2&#10;\\\\\\&#10;i\cdot \sqrt{(2^3)^2}~~+~~6i\implies 2^3i~+~6i\implies 8i+6i\implies 14i
7 0
3 years ago
Evaluate f(x) = 2x - 4 for x = 5
algol13
Plug in x = 5
f(5) = 2(5) - 4
f(5) = 10 - 4
Solution: f(5) = 6
8 0
3 years ago
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