First you solve the inequality. Add the variables that can be added together. That would be -3 + 1=2. Now the equation is 2 + x<6. After you change the 2 into a negative and put it under the 6 and subtract. that is 3. 3 is the number you put on the number line. When you fine and plot three you make a dot above it. You fill in the dot since the less then sign has a line beneath it. Then you draw a line from the dot to the end of the number line from the direction the sign is facing. It’s a less then sign, so you would draw the line to the left.
Answer:
The number line shows the graph of an inequality: A number line is shown from negative 5 to positive 5 with increments of 0.5. All the whole numbers are labeled on the number line. An empty circle is shown on the third mark to the left of 0. The region to the left of the empty circle is shaded. Which statement explains whether −3.5 can be a value in the shaded region? Yes it can, because −3.5 lies to the right of −1.5. No it cannot, because −3.5 lies to the left of −1.5. Yes it can, because −3.5 lies to the left of −1.5. No it cannot, because −3.5 lies to the right of −1.5.
Which table shows a proportional relationship between x and y? x 2 4 5 6 y 6 12 18 21 x 1 3 4 5 y 50 150 200 250 x 3 5 7 8 y 1.5 2.5 3 4.5 x 1 2 3 6 y 1.5 3 6 9 the graph of a proportional relationship passes through (12,16) and (1,y) find y. can someone please walk me through this?
The correct question in the attached figure
we know that
the length of Q is 25% more than the length of p
so
length Q=1.25*40--------> 50 cm
the area of Q is 10% less than the area of p
Area Q=50*y
Area P=40*x
so
50*y=0.90*[40*x]---------> 50*y=36*x-------> x/y=50/36---> 25/18
the answer is
the ratio x:y is 25:18
Answer:
B. The statement is false. This is true only if θ is an acute angle in a right triangle.
Step-by-step explanation:
Trigonometric ratio formula can only be applied to define the relationship between the angles of a right triangle and its side lengths.
Therefore, it is impossible to define or find the tan θ of "any triangle". It only applies to right angled triangles.
In the case of a right triangle, given a reference angle, θ, tan θ = side lenght opposite to θ ÷ side lenght adjacent to θ (tan θ =
.
A right triangle has two acute angles and 1 right angle that which is 90°.
Therefore, we can conclude that:
"B. The statement is false. This is true only if θ is an acute angle in a right triangle."