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dalvyx [7]
3 years ago
9

A rectangular prism has a length of 12 centimeters, a width of 6 centimeters, and a height of 9 centimeters. A cross section is

formed by the prism and a plane that intersects the prism as shown. Find the perimeter of the cross section.
Mathematics
1 answer:
Klio2033 [76]3 years ago
3 0

Answer:

<h2>The perimeter of the cross section is 30 centimeters.</h2>

Step-by-step explanation:

In this problem we have the intersection of a rectangular prism an a plane.

The dimensions of the rectangular plane are

l=12cm\\w=6cm\\h=9cm

Assuming the plane is cutting the prism horizontally, the cross section would have dimensions

w=6cm\\l=9cm

Because only the height would be cut.

So, the perimeter of the rectangle cross-section is

P_{cross}=2(l+w)=2(6+9)=2(15)=30cm

Therefore, the perimeter of the cross section is 30 centimeters.

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Answer:

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Step-by-step explanation:

The given equation is written in slope-intercept form:

y=mx+b

where:

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  • <em>b is the y-intercept</em>
  • <em>x and y are the corresponding coordinate points (x,y)</em>

The slope is 2:

When two lines are perpendicular, their slopes will be opposite reciprocals. Find the slope of the line perpendicular to the given equation:

m_{1}=2

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Flip the fraction (reciprocal):

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Now make an equation written in point-slope form:

y-y_{1}=m(x-x_{1})

where:

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Insert information:

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Simplify to slope-intercept form. Solve for y:

Use the distributive property:

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Add 3 to both sides to isolate the variable:

y-3+3=-\frac{1}{2} x-1+3\\\\y=-\frac{1}{2} x+2

:Done

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