It looks like the given equation is
sin(2x) - sin(2x) cos(2x) = sin(4x)
Recall the double angle identity for sine:
sin(2x) = 2 sin(x) cos(x)
which lets us rewrite the equation as
sin(2x) - sin(2x) cos(2x) = 2 sin(2x) cos(2x)
Move everything over to one side and factorize:
sin(2x) - sin(2x) cos(2x) - 2 sin(2x) cos(2x) = 0
sin(2x) - 3 sin(2x) cos(2x) = 0
sin(2x) (1 - 3 cos(2x)) = 0
Then we have two families of solutions,
sin(2x) = 0 or 1 - 3 cos(2x) = 0
sin(2x) = 0 or cos(2x) = 1/3
[2x = arcsin(0) + 2nπ or 2x = π - arcsin(0) + 2nπ]
… … … or [2x = arccos(1/3) + 2nπ or 2x = -arccos(1/3) + 2nπ]
(where n is any integer)
[2x = 2nπ or 2x = π + 2nπ]
… … … or [2x = arccos(1/3) + 2nπ or 2x = -arccos(1/3) + 2nπ]
[x = nπ or x = π/2 + nπ]
… … … or [x = 1/2 arccos(1/3) + nπ or x = -1/2 arccos(1/3) + nπ]
Answer:
10.8
Step-by-step explanation:
becaue you need to mutiply all sides
Answer:
3.5 years
Step-by-step explanation:
Each year, Louis earned
$1500×0.035 = $52.50
in interest.
The amount of interest that had been credited to his account at the time of withdrawal was ...
$1683.75 -1500.00 = $183.75
Then the length of time the money had been in the account was ...
$183.75/($52.50/yr) = 3.5 yr
_____
<em>Comment on the problem</em>
We have assumed the account earned simple interest. Given the neatness of the answer, we believe that to be a correct assumption.
Answer:
a
Step-by-step explanation:
B. 5
the minimum is where the end of the left tail is. the first quartile is where the beginning of the box is, the mid is in the middle of the box, the 3rd quartile is at the end of the box and the maximum is the end of the right tail.
