Question

How do you solve each system of equations?

Answer 1

Answer:

$x=1,y=3,z=1$

Step-by-step explanation:

$4x-4y+4z=-4$

$4x=-4+4y-4z$

$x=-1+y-z$

Substitute  $x=-1+y-z$ into second equation:

$4\left(-1+y-z\right)+y-2z=5$

$-4+4y-4z+y-2z=5$

$5y-6z-4=5$

$y=\frac{6z+9}{5}$

Substitute $x=-1+y-z$ and $y=\frac{6z+9}{5}$ into the third equation:

$\frac{-41z-54}{5}+3=-16$

$-41z-54=-95$

$z=1$

Substitute $z=1$ into $y=\frac{6z+9}{5}$:

$y=3$

Plug in y and z values into $x=-1+y-z$:

$x=1$