54+9= 63 m = distance and time=35 sec hence, speed= 63/35=9/5=1.8 m/s
time taken to reach water surface= distance/speed=54/1.8=30 sec
that'd be a segment.
⭕-------------------------------------⭕
Answer:
Her second lap was <u>8%</u> better when compared to her first lap.
Step-by-step explanation:
Given:
Emily ran her first lap in 75 seconds she ran her second lap in 69 seconds.
Now, to find how much better was her second lap when compared to her first lap.
Emily ran her first lap in 75 seconds.
Emily ran her second lap in 69 seconds.
So, we get the difference in seconds:

<u><em>Thus, in her second lap she was 6 seconds better than first.</em></u>
Now, to get the percentage of her first lap better than second:



Therefore, her second lap was 8% better when compared to her first lap.
Okkkkkkkkkkkkkkkkkkkkkkkkkkk
Answer:
m(arc ZWY) = 305°
Step-by-step explanation:
8). Formula for the angle formed outside the circle by the intersection of two tangents or two secants is,
Angle formed by two tangents = 
= 
= 
= 40°
9). Following the same rule as above,
Angle formed between two tangents = 
125 = ![\frac{1}{2}[m(\text{major arc})-m(\text{minor arc})]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Bm%28%5Ctext%7Bmajor%20arc%7D%29-m%28%5Ctext%7Bminor%20arc%7D%29%5D)
250 = ![[m(\text{arc ZWY})-m(\text{arc ZY})]](https://tex.z-dn.net/?f=%5Bm%28%5Ctext%7Barc%20ZWY%7D%29-m%28%5Ctext%7Barc%20ZY%7D%29%5D)
250 = m(arc ZWY) - 55
m(arc ZWY) = 305°
Therefore, measure of arc ZWY = 305° will be the answer.
10). m(arc BAC) = ![\frac{1}{2}([m(\text{arc BDC})-m(\text{arc BC})])](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Bm%28%5Ctext%7Barc%20BDC%7D%29-m%28%5Ctext%7Barc%20BC%7D%29%5D%29)
= 
= 
= 74°