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Scilla [17]
3 years ago
11

the table shows the number of yards a football player runs in each quater of a game find the mean number of yards the player run

s per quarter

Mathematics
1 answer:
zalisa [80]3 years ago
7 0

We know the number of yards run per quarter:

  • Quarter 1: -2 yards
  • Quarter 2: 14 yards
  • Quarter 3: -18 yards
  • Quarter 4: -6 yards

\text{Mean number of yards run} = \frac{\text{Sum of yards run across quarters}}{\text{Total number of quarters}}

Sum of yards run across quarters = (-2) + 14 + (-18) + (-6) = -12

Total number of quarters = 4

⇒ \text{Mean number of yards run} = \frac{\text{Sum of yards run across quarters}}{\text{Total number of quarters}}

⇒ \text{Mean number of yards run} = \frac{-12}{4} = -3

Hence, he ran -3 yards per quarter

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How do you simplify (-5x^5+14)-(11x^2+1+11x^5)
lord [1]
(-5x ⁵+14)-(11x ²+1+11x ⁵)
Like terms: -5x ⁵-11x ⁵ = -16x ⁵
Like terms also: 14-1 = 13
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3 years ago
How is the series 5+11+17…+251 represented in summation notation?
NISA [10]

Answer:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

Step-by-step explanation:

Given:

  • Series 5+11+17+...+251

To find:

  • Summation notation of the given series

Summation Notation:

\displaystyle \large{\sum_{k=1}^n a_k}

Where n is the number of terms and \displaystyle \large{a_k} is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

  • Arithmetic Series

A series that has common difference.

  • Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

  • 11-5 = 6
  • 17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

\displaystyle \large{a_n=a_1+(n-1)d}

Where \displaystyle \large{a_n} is the nth term, \displaystyle \large{a_1} is the first term and \displaystyle \large{d} is the common difference:

So for our general term:

\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}

And for number of terms, substitute \displaystyle \large{a_n} = 251 and solve for n:

\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}

Now we can convert the series to summation notation as given the formula above, substitute as we get:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

5 0
2 years ago
Slope -1 passes through (7,2)
kvv77 [185]
Y = mx + b
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so ur equation of this line is : y = -1x + 9.....can also be written as :
y = -x + 9....or if u need it in standard form, it is : x + y = 9
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