which means none of the above are correct, unless you have a different definition of
.
Answer:
i cant see the pic sorry
Step-by-step explanation:
Let r = (t,t^2,t^3)
Then r' = (1, 2t, 3t^2)
General Line integral is:
The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector
Fortunately, this simplifies nicely with a 'u' substitution.
Let u = 1+4t^2 +9t^4
du = 8t + 36t^3 dt
After integrating using power rule, replace 'u' with function for 't' and evaluate limits:
Answer: 0.49 mi
Step-by-step explanation:
First find the half circumference of the circular pond as this will show the total distance your friend has to walk:
= (π * diameter) / 2
= (22/7 * 0.85) / 2
= 1.34 mi
Your friend is going to walk 1.34 and you will walk 0.85.
Difference is:
= 1.34 - 0.85
= 0.49 mi
Answer:
Now, 3x 2+x+5⩾0
This is because b² −4ac=1−4×5×3
=−59 (roots are imaginary)
3x²+x+5=(x−3)² =x²+9−6x and x−3⩾0
2x²+7x−4=0
2x²+8x−x−4=0
2x(x+4)−1(x+4)=0
(2x−1)(x+4)=0
x= 1/2 and−4 but x≥3
∴ No solution.
lol hehehe