The two rational expressions will be; (x + 2)/(x² - 36) and 1/(x² + 6x)
<h3>How to simplify Quadratic Expressions?</h3>
We want to determine the two rational expressions whose difference completes the equation.
The two rational expressions will be;
(x + 2)/(x² - 36) and 1/(x² + 6x)
Now, this can be proved as follows;
Step 2 [(x + 2)/(x² - 36)] - [1/(x² + 6)]
= [(x + 2)/(x + 6)(x - 6)] - [1/(x(x + 6)]
Step 3; By subtracting, we have;
[x(x + 2) - (x - 6)]/[x(x + 6)(x - 6)]
Step 4; By further simplification of step 3, we have;
[x² + x + 6]/[x(x-6)(x + 6)]
Read more about Quadratic Expressions at; brainly.com/question/1214333
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This should be a rotation!
<u>Answer:</u>
The range of the function y = 2cos x is -2 <y < 2 .
<u>Step-by-step explanation:</u>
We know that cos (0) = 1 and cos (π) = - 1 are the two extreme values which cos x assume when x ∈ R and it is also that cos (x) is a continuous periodic function with period 2π when x ∈ R ,
since ,
cos (x + 2π) = cos x
So, the range of the function y = 2cos x is -2 <y < 2 .
Answer:
$27.324
Step-by-step explanation:
$25.30 • $1.08 = $27.324
Answer:
C. Incomplete sentences
Step-by-step explanation:
