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antoniya [11.8K]

3 years ago

13

Can u please give me an answer best gets the brainliest

1 answer:

riadik2000 [5.3K]3 years ago

8 0

100 cm = 1 m, so the conversion factor must be either 100 cm/1 m or 1 m/100 cm. Since you want to end up with cm, you need cm in the numerator. Then the m in the denominator will cancel out the given m. The answer is B.

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Examine the following graph of y=1/4x+2.

choli [55]

Answer: 9/4

Step-by-step explanation:

The slope-intercept form is y = m x + b , where m is the slope and b is the y-intercept. y = m x + b Find the values of m and b using the form y = m x + b . m = 1/4 b = 2 The slope of the line is the value of m , and the y-intercept is the value of b . Slope: 1/4 y-intercept: 2 Any line can be graphed using two points. Select two x values, and plug them into the equation to find the corresponding y values. Choose 0 to substitute in for x to find the ordered pair. y = 2 Choose 1 to substitute in for x to find the ordered pair. Tap for fewer steps... Replace the variable x with 1 in the expression. f ( 1 ) = 1 4 + 2 Simplify the result. The y value at x = 1 is 9/4 . y = 9/4

3 0

3 years ago

Multiply 3/5 x 35 I don’t know!

aleksley [76]

Answer:The answer is 21

Step-by-step explanation:

simplify-3/5

3/5*35=21

3 0

3 years ago

Read 2 more answers

After school Marcy can start walking dogs by 3:15pm she wants to be dont walking by 6:00 in time for dinner if she does one dog

evablogger [386]

She can walk 3 dogs before dinner

5 0

3 years ago

Read 2 more answers

A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch

ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

$P$ = a person passes the security system

$H$ = a person is a security hazard

Given:

$P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01$

Then,

$P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\$

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: $P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The value of P (P) is:

$P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412$

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

$P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1$

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0

3 years ago

Use Law of Sines or Law of Cosines to solve for the missing parts of each triangle

ella [17]

Answer:

$x = 9.7$

Step-by-step explanation:

Given

The attached triangle

Required

Find x

Using law of sine, we have:

$\frac{a}{sin A} = \frac{b}{Sin B}$

So, we have:

$\frac{x}{sin 32} = \frac{18}{Sin 100}$

Make x the subject

$x = \frac{18 * sin 32}{Sin 100}$

$x = \frac{18 * 0.5299}{0.9848}$

$x = 9.685$

$x = 9.7$ -- approximated

4 0

3 years ago