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d1i1m1o1n [39]
3 years ago
9

The larger of two numbers is 12 times the smaller number. if the sum of two numbers is 15,600, find the two numbers.​

Mathematics
1 answer:
xeze [42]3 years ago
4 0

Answer:

<h3>             1200 and 14400</h3>

Step-by-step explanation:

n   - smaller number

The larger number is 12 times the smaller number

12n  - larger number

n + 12n = 13n  - the sum of these numbers

13n = 15600

÷13        ÷13

 n = 1200

12n = 12•1200 = 14400

Check:  14400+1200 = 15600

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4 thousands 7 hundreds = 47 _​
DanielleElmas [232]

Answer:

4700

Step-by-step explanation:

4 thousands = 4000

7 hundreds = 700

Add those numbers together and you get 4700

Hope this helps

6 0
4 years ago
In the following exercises, translate into an equation and solve
Citrus2011 [14]

Answer: 6 children

Step-by-step explanation:

Given:

Children - 24

Groups - 4

Number of children per group - x

Solve:

24 ÷ 4 = x

x = 6

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7 0
2 years ago
Please answer quick!
tatuchka [14]
4 * (25 * 1.2) = (4 * 25) * 1.2
3 0
3 years ago
Read 2 more answers
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Ainat [17]

Answer:

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7 0
3 years ago
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Simplify the expression by factoring, showing the steps in your work.
alexdok [17]

Given:

$\frac{12 x^{2}+31 x+7}{16 x^{2}+8 x+1}

To find:

The simplified expression by factoring.

Solution:

Let us factor the numerator:

12 x^{2}+31 x+7

31x can be written as 3x + 28x.

    =\left(12 x^{2}+3 x\right)+(28 x+7)

Take 3x common in 1st two terms and 7 common in next two terms.

    =3 x(4 x+1)+7(4 x+1)

Make sure the remaining terms in the both brackets must be same.

Now, take out common factor (4x + 1).

    =(4 x+1)(3 x+7)

In the same way, factorize the denominator:

16 x^{2}+8 x+1

8x can be written as 4x + 4x.

     =(16 x^{2}+4 x)+(4x+1)

Take 4x common in 1st two terms and 1 common in next two terms.

     =4x(4 x+1)+1(4x+1)

Make sure the remaining terms in the both brackets must be same.

Now, take out common factor (4x + 1).

     =(4x+1)(4x+1)

Substitute the terms we found for numerator and denominator:

$\frac{12 x^{2}+31 x+7}{16 x^{2}+8 x+1}=\frac{(4 x+1)(3 x+7)}{(4 x+1)(4 x+1)}

Cancel the common factors.

                        $=\frac{3 x+7}{4 x+1}

The simplified expression is \frac{3 x+7}{4 x+1}.

3 0
4 years ago
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