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3 years ago

Help me find my answer

Mathematics

1 answer:

Sergeu [11.5K]3 years ago

4 0

Step-by-step explanation:

3 cookies= 240 cal

∴ 1 cookie= 240÷3 cal

∴ 5 cookies= (240÷3) × 5

⇒ 240÷3= 80

⇒ 80 × 5= 400

[ans] 400 cal

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8x+5 3x+8 Find the measurement of x!!

Soloha48 [4]

Answer:

Step-by-step explanation: look at the picture

8 0

2 years ago

What is the probability of drawing the compliment of a king or a

inna [77]

Answer:

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

Step(i):-

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

$n( E_{1} ) = 4 _{C_{1} } = 4$

Let E₂ be the event of the card drawn being a queen

$n( E_{2} ) = 4 _{C_{1} } = 4$

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

step(ii):-

The probability of drawing of a king or a queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

$= \frac{4}{52} + \frac{4}{52}$

P( E₁ U E₂ ) = $\frac{8}{52}$

step(iii):-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards

$P(E_{1}UE_{2}) ^{-} = 1- P(E_{1} U E_{2} )$

$P(E_{1}UE_{2}) ^{-} = 1- \frac{8}{52}$

$P(E_{1}UE_{2}) ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846$

Conclusion:-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

5 0

2 years ago

Use the diagram shown.

PSYCHO15rus [73]

Answer:

Step-by-step explanation:

8 0

3 years ago

4 • (6 – 4) 2 ÷ 2

Dmitry_Shevchenko [17]

Answer:

Cary is wrong

Step-by-step explanation:

4* (6-4)= 4* 2=8

I think it is saying (8*2) divided by to, which in that case is 8,

but if it is asking 8 (2/2) then that would also be 8 I believe. I really hope this is correct and you have a great day :)

5 0

2 years ago

Read 2 more answers

2. CHEMISTRY How many liters of 15% acid and

Wewaii [24]

Answer:

<h3> 26²/₃ liters of 15% acid and 13¹/₃ liters of 33% acid</h3>

Step-by-step explanation:

Concentration Amount of Amount

of Solution Solution (L) of Acid

15% x 0.15x

33% y 0.33y

21% 40 0.21•40

x + y = 40 ⇒ x = 40 - y

0.15x + 0.33y = 0.21•40

0.15(40 - y) + 0.33y = 0.21•40

6 - 0.15y + 0.33y = 8.4

0.18y = 2.4

y = 13¹/₃

x = 40 - 13¹/₃ = 26²/₃

8 0

2 years ago