Excuse me can you help me to resolve this (×+5) (4x-3)=0

Mathematics

1 answer:

GuDViN [60]3 years ago

6 0

Answer: x = 3/4 x = -5

Step-by-step explanation:

x+5=0

x=-5

4x-3=0

Add three to both sides

4x = 3

x=3/4

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Find the dimensions of a rectangle (in m) with area 1,728 m2 whose perimeter is as small as possible. (Enter the dimensions as a

lozanna [386]

Given :

Area of rectangle.

To Find :

The dimensions of a rectangle (in m) with area 1,728 m2 whose perimeter is as small as possible.

Solution :

Let, the dimensions of rectangle is x and y.

Area, A = xy.

x = A/y. ....1)

Perimeter, P = 2( x + y )

Putting value of x in above equation, we get :

$P = 2( y + \dfrac{A}{y})$

For minimum P,

$\dfrac{dP}{dx}=2( 1 - \dfrac{A}{x^2})=0\\\\A = x^2$

SO, it is a square.

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2 years ago

What is 6x^2-2x+1=0 plz help

Kazeer [188]

6x^2 - 2x + 1 is a quadratic formula from the form ax^2 + bx + c. This form of equation represents a parabola.
Finding 6x^2 - 2x + 1 = 0, means that you need to find the zeroes of the equation.
Δ = b^2 - 4ac
If Δ>0, the equation admits 2 zeroes and 6x^2 - 2x + 1 = 0 exists for 2 values of x.
If Δ<0, the equation doesn't admit any zero, and 6x^2 - 2x + 1 = 0 doesn't exist since the parabola doesn't intersect with the axe X'X
If Δ=0, the equation admits 1 zero, which means that the peak of the parabola is touching the axe X'X.

In 6x^2 - 2x + 1, a=6, b=-2, and c =1.
Δ= b^2 - 4ac
Δ=(-2)^2 - 4(6)(1)
Δ= 4 - 24
Δ= -20
Δ<0 so the parabola doesn't intersect with the Axe X'X, which means there's no solution for 6x^2 - 2x + 1 = 0.

I've added a picture of the parabola represented by this equation under the answer.

Hope this Helps! :)