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coldgirl [10]
3 years ago
8

The probability of even a is x, and the probability of even b is y, if the two evens are independent, which of these conditions

must be true?
Mathematics
1 answer:
bonufazy [111]3 years ago
4 0

I think you meant to write "event" instead of "even".

P(A) = x

P(B) = y

P(A and B) = P(A)*P(B)

P(A and B) = x*y

you multiply the two probability values. This rule only works because the two events are independent.

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7/7 also known as a whole (1)

Step-by-step explanation:

All you have to do is add 4 and 3 then keep the denominator the same (7)

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The graph below shows the height an elevator travels, y, in x seconds:
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Answer:

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Step-by-step explanation:

The "rate of change" is taken to mean the "rise" divided by the "run". Here, adjacent points differ in their y-value by 25 ft and their x-value by 1 second.

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Usually, we're just interested in the numerical value: 25.

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<em>Additional comment</em>

The graph is mis-labeled. It is not showing "rate of ascent." It is showing height as a function of time. The "rate of ascent" is the <em>slope</em> of the line on the graph, not its <em>value</em>.

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4 0
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Mrac [35]

Convert to cylindrical coordinates:

x=x

y=r\cos\theta

z=r\sin\theta

Then E is the set of points (r,\theta,x) such that 0\le r\le1, 0\le\theta\le2\pi, and 7y^2+7z^2\le x\le7 or 7r^2\le x\le7.

Now

\displaystyle\iiint_E5x\,\mathrm dV=5\int_0^{2\pi}\int_0^1\int_{7r^2}^7xr\,\mathrm dx\,\mathrm dr\,\mathrm d\theta=\boxed{\frac{245\pi}3}

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