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coldgirl [10]
3 years ago
8

The probability of even a is x, and the probability of even b is y, if the two evens are independent, which of these conditions

must be true?
Mathematics
1 answer:
bonufazy [111]3 years ago
4 0

I think you meant to write "event" instead of "even".

P(A) = x

P(B) = y

P(A and B) = P(A)*P(B)

P(A and B) = x*y

you multiply the two probability values. This rule only works because the two events are independent.

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The length of an object in feet is equal to 3 times it's length in yards.
qwelly [4]

Answer:

12

Step-by-step explanation:

3 times X is equal to 36.

X is the number were going to solve for, and since you need 3 groups of 12 to solve for 36, it would be 12.

5 0
3 years ago
A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sam
Scorpion4ik [409]

Answer:

After use the formula we got the following result for the 90% confidence interval (0.13 <p<0.34)

And the conclusion for this case would be:

e. With 90% confidence, the proportion of all students who take notes is between 0.13 and 0.34.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Description in words of the parameter p

p represent the real population proportion of students who take notes

\hat p represent the estimated proportion of students who take notes

n is the sample size required  

z_{\alpha/2} represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

Confidence interval

The confidence interval for a proportion is given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 90% confidence interval the value of \alpha=1-0.90=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.64  

After use the formula we got the following result for the 90% confidence interval (0.13 <p<0.34)

And the conclusion for this case would be:

e. With 90% confidence, the proportion of all students who take notes is between 0.13 and 0.34.

6 0
3 years ago
Mr. Kirkpatrick took a survey of his two math classes asking how many siblings each student has. The results are in the histogra
Amiraneli [1.4K]

Answer:

A and D.

Step-by-step explanation:

Resort to graphs.

8 0
3 years ago
8 minus 3 minus (|negative 1| minus 9)
kaheart [24]

8 minus 3 equals 5

Negative 1 minus 9 is negative 10

5 times negative 10 is <u>negative 50.</u>

6 0
3 years ago
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Write 15.27 as a mixed number.
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Answer:

15 27/100 is 15.27 as a mixed number

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3 years ago
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