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3 years ago

8

The probability of even a is x, and the probability of even b is y, if the two evens are independent, which of these conditions

must be true?

1 answer:

bonufazy [111]3 years ago

4 0

I think you meant to write "event" instead of "even".

P(A) = x

P(B) = y

P(A and B) = P(A)*P(B)

P(A and B) = x*y

you multiply the two probability values. This rule only works because the two events are independent.

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Acrosonic's production department estimates that the total cost (in dollars) incurred in manufacturing x ElectroStat speaker sys

il63 [147K]

Answer:

a) $P(x)=-0.042x^2+530x-18000$

b) $P'(x)=-0.084x+530$

c)

$P'(4000)=194$

$P'(9500)=-268$

Step-by-step explanation:

a)

We know that Revenue is our total income and cost is our total cost. Thus, profit is what's left after cost is subtracted from Income (revenue). Thus, we can say:

P(x) = R(x) - C(x)

Finding Profit Function (P(x)):

$P(x) = R(x) - C(x)\\P(x) = -0.042x^2+800x-(270x+18000)\\P(x)=-0.042x^2+800x-270x-18000\\P(x)=-0.042x^2+530x-18000$

This is the profit function.

b)

The marginal profit is the profit earned when ONE ADDITIONAL UNIT of the product is sold. This is basically the rate of change of profit per unit. We find this by finding the DERIVATIVE of the Profit Function.

Remember the power rule for differentiation shown below:

$\frac{d}{dx}(x^n)=nx^{n-1}$

Now, we differentiate the profit function to get the marginal profit function (P'):

$P(x)=-0.042x^2+530x-18000\\P'(x)=2(-0.042)x^1+530x^0-0\\P'(x)=-0.084x+530$

This is the marginal profit function , P'.

c)

We need to find P'(4000) and P'(9500). So we basically put "4000" and "9500" in the marginal profit function's "x". The value is shown below:

$P'(x)=-0.084x+530\\P'(4000)=-0.084(4000)+530\\P'(4000)=194$

and

$P'(x)=-0.084x+530\\P'(9500)=-0.084(9500)+530\\P'(9500)=-268$

6 0

3 years ago

mr chu is slicing 4 cantaloupes for his class . There are 24 students in the class. If he cuts the cantal to make an equal porti

HACTEHA [7]

1/6 because 4/24 simplifies to 1/6

4 0

3 years ago

Based on past experience, a telemarketing firm has found that calls to prospective customers take an average of 2.0 minutes, wit

xenn [34]

Answer: Our required probability would be 0.9641.

Step-by-step explanation:

Since we have given that

Number of hours he works a day = 8

So, Number of minutes he worked in a day = $8\times 60=480\ minutes$

Number of calls = 220

So, Average $=\bar{x}=\dfrac{480}{220}=2.18\ minutes$

Standard deviation $=s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.5}{\sqrt{220}}=0.10$

Mean = μ = 2.0 minutes

Standard deviation = σ = 1.5 minutes

Using the normal distribution, we get that

$z=\dfrac{\bar{x}-\mu}{s}\\\\z=\dfrac{2.18-2.0}{0.10}\\\\z=1.8$

So, the probability that Albert will meet or exceed his quota would be

$P(X\leq 2.18)=P(z\leq 1.8)=0.9641$

Hence, our required probability would be 0.9641.

6 0

3 years ago

A truck travels 2,400 miles in 60 hours, going the same distance each hour.

expeople1 [14]

2400miles/60hours
40miles/hour
Answer is D

6 0

2 years ago

Read 2 more answers

What number is 100 less than 84 tens

Gre4nikov [31]

740, 84 x 10 - 100 = 740

8 0

3 years ago

Read 2 more answers