Explanation:
The last one is the answer
hope it's correct
Answer:
Point 3 for kinetic, points 1 and 5 for potential
Explanation:
There is one point that the ball has the most kinetic energy it is at point 3. Point 3 has the most kinetic energy because it has gained the most speed since it was dropped and it also is right before it starts slowing down from trying to go up again. Points 1 and 5 have the most potential energy. When the ball is at point 1 or 5 it is at its maximum height thus it cannot swing any further, so it stops for a split second and gains a large amount of potential energy before it is released into kinetic energy when it falls back down.
Mitochondria. The “powerhouses” of the cell, mitochondria are oval-shaped organelles found in most eukaryotic cells. As the site of cellular respiration, mitochondria serve to transform molecules such as glucose into an energy molecule known as ATP (adenosine triphosphate).
Answer:
Hi how are you doing today Jasmine
Answer:
The correct order would be
- Glucose
- ATP→ADP
- H₂O
- Pyruvate
- CO₂
Explanation:
Following reactions occur in Glycolysis and Kreb's Cycle
- Phosphorylation of Glucose- In the first step of glycolysis, Glucose is converted into Glucose-6-Phosphate using 1 ATP molecule by Hexokinase enzyme. One phosphate group from ATP is attached to glucose by the enzyme, thus forming ADP.
- Dehydration- In the ninth step of Glycolysis, each of two molecules of 2-Phosphoglycerate are converted to Phosphoenol Pyruvate, by Enolase enzyme, releasing two H₂O molecules.
- Formation of Pyruvate- In the last or tenth step of Glycolysis, each of two molecules of Phosphoenol Pyruvate are converted to Pyrutave using an ATP by the enzyme Pyruvate Kinase.
- Oxidation Of Pyruvate to Acetyl-CoA- Before the Kreb's Cycle starts, the Pyruvate molecule obtained from the Glycolysis undergoes oxidative decarboxylation producing Acetyl-CoA and release of CO₂ and NADH.
