Answer:
9.0 m
Explanation:
Applying
V = kq/r......................... Equation 1
Where V = Electric potential, q = charge, r = distance, k = Coulomb's constant.
make r the subject of the equation
r = kq/V................... Equation 2
From the question,
Given: q = 1.00×10⁻⁵ C, V = 10000 V
Constant: k = 9.0×10⁹ N⋅m²/C²
Substitute these values into equation 2
r = (9.0×10⁹×1.00×10⁻⁵)/10000
r = 9.0 m
<span>We need to start by finding the surface area of the pool.
50 meters multiplied by 25 meters gives us 1250 square meters.
1250 square meters multiplied by .065 (6.5 cm in meters) gives us a volume of 81.25 cubic meters of water that needs to be pumped out of the pool.
There are 1000 liters in a cubic meter so this is 81250 liters. Divide by 4.2 to find the number of seconds required to pump out this much water and we get 19345.2 seconds. This equals approximately 5.37 hours.</span>
Answer:
X = 69.1 x 10⁻⁶ m = 69.1 μm
Explanation:
The relationship between the motion of the moveable mirror and the fringe count of the Michelson's Interferometer is given by the following formula:
d = mλ/2
where,
d = distance moved by the mirror = X = ?
m = No. of Fringes counted = 246
λ = wavelength of light entering interferometer = 562 nm = 5.62 x 10⁻⁷ m
Therefore,
X = (246)(5.62 x 10⁻⁷ m)/2
Therefore,
<u>X = 69.1 x 10⁻⁶ m = 69.1 μm</u>
The greatest difference between high and low tide is around New Moon and Full Moon. During these Moon phases, the solar tide coincides with the lunar tide because the Sun and the Moon are aligned with Earth, and their gravitational forces combine to pull the ocean's water in the same direction.
Your answer is B Full moon
