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irina [24]
3 years ago
8

I have to write an essay about Quantum Mechanics. I need to know everything about it. Please Help!

Physics
2 answers:
Studentka2010 [4]3 years ago
6 0

ananı var ya ananı

kodumun abd lisi aptal cajhil özürlü

Neporo4naja [7]3 years ago
5 0

Quantum mechanics means dealing with physics at a very small level. Or u can say microscopic level. Studying physics at sub atomic level

Study regarding protons, electrons and quarks include in this study.

Also the laws of physics at normal level fail in quantum mechanics.

Laws like uncertainty principal of Heisenberg, wave nature, are there

(So if u want to write an essay, first u can tell about) the difference between normal sized objects and the subatomic ones. And how physics act upon them

Then u can write about how laws fail for microscopic things so we need to study quantum mechanics.

And elaborate every paragraph like i ve written in points.

hope that will make ur essay complete ♥

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I what is the resistance of
Lynna [10]
The resistance of a conductor is given by:
R= \frac{\rho L}{A}
where
\rho is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area

We can use this formula to solve both parts of the problem.

a) The length of the copper wire is L=1.0 m. Its diameter is d=0.50 mm, so its radius is 
r= \frac{d}{2}=0.25 mm=0.25 \cdot 10^{-3} m
And its cross-sectional area is
A=\pi r^2 = \pi (0.25 \cdot 10^{-3}m)^2 = 1.96 \cdot 10^{-7} m^2
The copper resistivity is \rho=1.68 \cdot 10^{-8} \Omega m, therefore the resistance of this piece of wire is
R= \frac{\rho L}{A}= \frac{(1.68 \cdot 10^{-8} \Omega m)(1.0 m)}{1.96 \cdot 10^{-7} m^2}=  8.57 \cdot 10^{-2} \Omega

b) The length of this piece of iron is L=10 cm=0.10 m. Its cross-sectional size is L=1.0 mm=0.001 m, so its cross-sectional area is
A=L^2 = (0.001 m)^2 =1 \cdot 10^{-6}m^2
The iron resistivity is \rho = 9.71 \cdot 10^{-8} \Omega m, therefore the resistance of this piece of wire is
R= \frac{\rho L}{A}= \frac{(9.71 \cdot 10^{-8} \Omega m)(0.10 m)}{1.0 \cdot 10^{-6} m^2}=9.71 \cdot 10^{-3} \Omega

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Answer:

Required rate of return = 18.5 %

Explanation:

given,                            

rate of inflection = 4 %

risk free rate = 3 %                      

market risk premium = 5 %                    

firm has a beta  = 2.30                                  

rate of return has averaged 15.0% over the last 5 years

now,                                                                      

Nominal risk free rate = risk free rate  + inflation

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Required rate of return = Nominal risk free rate + β (RPM)

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