The resistance of a conductor is given by:

where

is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area
We can use this formula to solve both parts of the problem.
a) The length of the copper wire is L=1.0 m. Its diameter is d=0.50 mm, so its radius is

And its cross-sectional area is

The copper resistivity is

, therefore the resistance of this piece of wire is

b) The length of this piece of iron is L=10 cm=0.10 m. Its cross-sectional size is L=1.0 mm=0.001 m, so its cross-sectional area is

The iron resistivity is

, therefore the resistance of this piece of wire is
Answer:........u are so sweet
Answer:
Required rate of return = 18.5 %
Explanation:
given,
rate of inflection = 4 %
risk free rate = 3 %
market risk premium = 5 %
firm has a beta = 2.30
rate of return has averaged 15.0% over the last 5 years
now,
Nominal risk free rate = risk free rate + inflation
= 3% + 4%
= 7%
Required rate of return = Nominal risk free rate + β (RPM)
= 7% + 2.3 x 5.0%
Required rate of return = 18.5 %
so you can see all the different categories at once. both as a whole and on an individual scale.
The average speed is 8 miles