Two trains are blowing their whistles. The first train is stationary, and the

345nm=____mm<br>I need to see how to work the problem out

Amanda [17]

Answer:

3.45×10⁻⁴mm (or 0.000345mm)

Explanation:

Use a method called dimensional analysis here. It involves a chain of conversions, so we'll need some conversions to work with.

1nm = 1×10⁻⁹m
1mm = 1×10⁻³m
345nm; which is given

If you knew the conversion from nanometers to millimeters then you could just do it in one step. But I don't, so I won't. Anyways, you put the conversions into fraction form like so:

1nm/1×10⁻⁹m
1mm/1×10⁻³m

And then orient them in a way where multiplying the two (or more in other instances) gives you the units you want. In this cas it's millimeters so you'll have:

(345nm)•(1×10⁻⁹m/1nm)•(1mm/1×10⁻³m)

Notice how all the units reduce except for mm. From here you just multiply across and should get 345×10⁻⁶mm which simplifies to 3.45×10⁻⁴mm.

3 0

3 years ago

PLZ HELP ME FAST! How does the placement of the metal coil closer or further away from the magnet affect the motor’s strength? W

love history [14]

A very long solenoid has a magnetic field inside which depends on the current in the wire and the number of turns per unit length of the solenoid. ... Adding more turns in the coil can also increase the total resistance of the wire.

3 0

3 years ago

A hungry 177177 kg lion running northward at 75.575.5 km/hr attacks and holds onto a 32.332.3 kg Thomson's gazelle running eastw

ValentinkaMS [17]

Answer: 73.2 km/hr

Explanation:

This is a momentum conservation type of problem, here we need to use the fact that the initial momentum is equal to the final momentum.

Remember that the momentum is written as:

P = m*v

m = mass

v = velicity

At the beginning, we have:

A lion of 177 kg running at velocity of 75.5 km/hr

Then the momentum of the lion is P1 = 177 kg*75.5 km/hr= (13,363.5)kg*km/hr

The gazelle has a mass of 32.3 kg, and a velocity of 60.6 km/hr

Then the momentum of the gazelle is:

P2 = 32.3kg*60.6km/hr = 1,957.38 kg*km/hr

The total initial momentum is equal to P1 + P2, then we have:

P = 1,957.38 kg*km/hr + 13,363.5 kg*km/hr = 15,320.9 kg*km/hr

Now, after the lion catches the gazelle, we can think it as only one object moving with mass equal to the mass of the lion plus the mass of the gazelle and velocity V

Then the final momentum will be:

Pf = (177kg + 32.3kg)*V = 209.3kg*V

And this needs to be equal to the initial momentum, then:

209.3kg*V = 15,320.9 kg*km/hr

V = (15,320.9 kg*km/hr)/209.3kg = 73.2 km/hr

Then the final speed of the lion-gazelle system is 73.2 km/hr

4 0

3 years ago

What does neutron absorption accomplish in a nuclear reactor

alexandr1967 [171]

Answer:

Its slows down the reaction

Explanation:

5 0

3 years ago

A clock battery wears out after moving 10,400 C of charge through the clock at a rate of 0.530 mA. (a) How long (in s) did the c

Sati [7]

Answer:

Explanation:

Given that:

Charge Q = 10400 C

current I = 0.530 mA

From our previous knowledge, we know that charge Q can be expressed as:

Q = I×t

where

I = current and t = time

∴

replacing our values

10400 = (0.530×10⁻³) t

t = 10400/(0.530×10⁻³)

t = 19622641.51 seconds

However, the required flow of electrons per seconds can be calculated by using the formula:

number of electrons/second = current (I)/ charge on electron

= (0.530×10⁻³)/(1.6×10⁻¹⁹)

= 3.3125×10¹⁵ electrons

7 0

3 years ago