Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8
Blababa [14]

From the given set of conditions, it's likely that you are asked to find the values of

and

at the point

.
By the chain rule, the partial derivative with respect to

is

and so at the point

, we have


Similarly, the partial derivative with respect to

would be found via

In a statistics class, students were asked how many siblings they have. Their responses are shown. 2, 3, 1, 3, 5, 3, 3, 3, 6, 3,
lbvjy [14]
Answer:
C as there is only 1 student with 2 siblings.
Y-9 + y/2 = 180
Add nine to each side
y+y/2=189
Multiply each side by two
2y+y=378
Add the y's together
3y=378
Divide it all by three
y=126
so, Angle B is 126 degrees
I hope that helps!
Can we get a picture please
Answer:
y = 3x -8
Step-by-step explanation:
I find it convenient to start with a version of the point-slope form of the equation for a line. That is, for point (h, k) and slope m, ...
y = m(x -h) +k
For your m=3 and (h, k) = (3, 1), this equation becomes ...
y = 3(x -3) +1
Eliminating parentheses puts this in the form you desire:
y = 3x -8