The given quadratic describes a parabola that opens upward. Its one absolute extreme is a minimum that is found at x = -3/2. The value of the function there is
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at
(-1.5, -3.25).
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For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
Answer:
2⁸ > 2.38 × 10² > 6³ > 2.16 × 10¹ >
, 300%
Step-by-step explanation:
Given numbers are,
2.38 × 10², √300, 2⁸, 300%, 6³, 2.16 × 10¹
We have to arrange these numbers in the decreasing order(from greatest to least)
2.38 × 10² = 2.38 × 100 = 238
√300 = 10√3 ≈ 17.32
2⁸ = 256
300% =
= 3
6³ = 216
2.16 × 10¹ = 21.6
Therefore, decreasing order (from the greatest to least) will be,
256 > 238 > 216 > 21.6 > 17.32 > 3
2⁸ > 2.38 × 10² > 6³ > 2.16 × 10¹ >
, 300%
Answer is F-1(x)= x/5-2 it is x over 5 minus 2
The answer is 10 i believe
The correct answer is b hope I helped