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Anika [276]
3 years ago
8

how many liters of 15% acid and 33% acid should be mixed to get 120 liter of 21% acid? what's the equation for this?

Mathematics
1 answer:
Mandarinka [93]3 years ago
5 0
\bf \begin{array}{lcccl}
&\stackrel{solution}{quantity}&\stackrel{\textit{\% of acid}}{amount}&\stackrel{\textit{liters of acid}}{amount}\\
&------&------&------\\
\textit{15\% acid}&x&0.15&0.15x\\
\textit{33\% acid}&y&0.33&0.33y\\ -----&------&------&------\\
mixture&120&0.21&25.2
\end{array}

\bf \begin{cases}
x+y=120\implies \boxed{y}=120-x\\
0.15x+0.33y=25.2\\
--------------\\
0.15x+0.33\left( \boxed{120-x} \right)=25.2
\end{cases}
\\\\\\
0.15x-0.33+39.6=25.2\implies -0.18x=-14.4
\\\\\\
x=\cfrac{-14.4}{-0.18}\implies x=80

how many liters will it be of the 33% acid?  well, y = 120 - x.
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Answer:

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Step-by-step explanation:

Given - DJ Titus is making a playlist for a radio show; he is trying to

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            Step 1 of 2 : If he has his choices narrowed down to 7 blues,

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To find - He wants to play no more than 4 reggae songs.

              How many different playlists are possible ?

Proof -

Given that he wants to play no more that 4 reggae songs.

So the possibility of choice of reggae song is 0, 1, 2, 3, 4

Now,

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Case II -

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Case III -

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Case IV -

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If 4 reggae song is selected

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So,

Total possible ways = 92,378+ 646,646+ 1,587,222+ 1,763,580+ 949,620

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Now,

Also the 10 songs selected can arranged themselves in 10! ways. ( because order of song played does not matter )

∴ we get

Different playlists possible = 10! × 5,039,446

                                          = 18287141644800

⇒Different playlists possible = 18287141644800

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