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3 years ago

Identify the domain and range of each of the graphs below. Domain: Range:

Mathematics

1 answer:

Anna11 [10]3 years ago

8 0

Answer:

Domain → (-∞, ∞)

Range → (-∞, ∞)

Step-by-step explanation:

Domain of a function is defined by the x-values or input values of the graph.

Similarly, Range of the function is defined by the y-values or output values from the graph.

From the picture attached,

x - values for the line shown in the graph vary from negative infinity to positive infinity.

Therefore, Domain of the function will be → (-∞, ∞)

And for every x-value there is a y-value, so Range of the function will be same as domain (varying from negative infinity to positive infinity) → (-∞, ∞)

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Find the exact solutions of x2 − 3x − 5 = 0 using the quadratic formula. Show all work! 75 points please help!!!!!

noname [10]

Answer:

$x=\dfrac{3+ \sqrt{29}}{2}, \quad \dfrac{3- \sqrt{29}}{2}$

Step-by-step explanation:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Given quadratic equation:

$x^2-3x-5=0$

Define the variables:

$\implies a=1, \quad b=-3, \quad c=-5$

Substitute the defined variables into the quadratic formula and solve for x:

$\implies x=\dfrac{-(-3) \pm \sqrt{(-3)^2-4(1)(-5)}}{2(1)}$

$\implies x=\dfrac{3 \pm \sqrt{9+20}}{2}$

$\implies x=\dfrac{3 \pm \sqrt{29}}{2}$

Therefore, the exact solutions to the given quadratic equation are:

$x=\dfrac{3+ \sqrt{29}}{2}, \quad \dfrac{3- \sqrt{29}}{2}$

Learn more about the quadratic formula here:

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8 0

2 years ago

Read 2 more answers

1.) You are the crew chief of the Algebra 2 formula racing team. Your current task is to

s344n2d4d5 [400]

Answer:

a). Mileage for carA= $\frac{2}{x}$ , and mileage for carB= $\frac{ 3x+2}{x(x+1)}$

b).total mileage for both is similar to average of them= $\frac{(mileageA + mileageB)}{2}$

= $\frac{5x+4}{2x(x+1)}[tex]mil/gal$

Step-by-step explanation:

It is given that the distance traveled by car $A=2x+2=2(x+1)$

And distance traveled by car $B= 3x+2$

We know the mileage is mile/gallon,

a).So mileage of car $A= \frac{distance traveled by car A}{gallos of fuel used}$

$=\frac{2x+2}{x^2 +x}\\ =\frac{2(x+1)}{x(x+1)} \\=\frac{2}{x}mil/gal$

Similarly , the mileage for car $B= \frac{distance traveled by car A}{gallons of fuel used}$

$=\frac{3x+2}{x^2+x} \\=\frac{3x+2}{x(x+1)}$ $mil/gal$

b).total mileage for both is similar to average of them= $\frac{(mileageA + mileageB)}{2}$

$=\frac{2x+2}{x(x+1)}+\frac{3x+2}{x(x+1)}\\ =\frac{2x+2+3x+2}{x(x+1)}\\=\frac{5x+4}{x(x+1)}mil/gal$

Now divide by 2 for total(average) mileage.

$\frac{\frac{5x+4}{x(x+1)} }{2}\\ =\frac{5x+4}{2x(x+1)} mil/gal$ .

Thus those are the answers.

4 0

3 years ago

Find the derivative of x^2+6x+9 at the point (2,6).

Pachacha [2.7K]

The derivative of the function is 2x+6.
At the particular point (2,6), plug in the x coordinate for x.
2(2)+6 = 10

Hope this helps :)

4 0

3 years ago

Which statement about this equation is true?

Viktor [21]

The equation has no solution because:

5(n+10)=5n+10n
5n+10n=5n+10n
I subtract 5n from both sides
10n=10n
Only one side is supposed to have the variable which is n, so the equation has no solution.

4 0

3 years ago

Please see attached! Surface area

grandymaker [24]

Surface area is 10 cm

8 0

3 years ago