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3 years ago

What is the value of y in the system of equations shown below?

Mathematics

1 answer:

vlabodo [156]3 years ago

6 0

just multiple the numbers.
for example 7×7 is - 49y
and 3×16 is - 48y

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20 Points!!!! PLEASE help!! Math!! Due soon!!

gogolik [260]

Answer:

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2 years ago

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icang [17]

Answer:

20 units

Step-by-step explanation:

The polygon has 4 vertices as indicated by the 4 coordinate points given.

(3, 1) and (8, 1) is a horizontal side of length 8 - 3 = 5

Similarly

(3, 6) and (8, 6) is the opposite horizontal side of length 8 - 3 = 5

Points (3, 1) and (3, 6) is a vertical side of length 6 - 1 = 5

(8, 1) and (8, 6) is the opposite side of length 6 - 1 = 5

The polygon is therefore a square of side 5 units.

Perimeter = 4 × 5 = 20 units

5 0

3 years ago

Supposed charity received a donation of $23.9 million. If this represents 54% of the charity donated funds what is the total amo

Tanzania [10]

Total amount of funds is $44.26 million.

Step-by-step explanation:

Given,

Donation received = $23.9 million

As it represents 54% of charity.

Let,

Total amount = x

Therefore,

54% of x = 23.9 million

$\frac{54}{100}*x=23.9\\0.54x=23.9$

Dividing both sides by 0.54

$\frac{0.54x}{0.54}=\frac{23.9}{0.54}\\x=\$44.26\ millions$

Total amount of funds is $44.26 million.

Keywords: percentage, division

Learn more about percentages at:

#LearnwithBrainly

8 0

3 years ago

An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click

Sergeeva-Olga [200]

Answer:

A. $\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

B. $\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

Step-by-step explanation:

Given that:

An investment of Amount = $8000

earns at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A) Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

$A = Pe^{rt}$

where;

$A = (8000) \ e ^{0.7t}$

The instantaneous rate of change = $\dfrac{dA}{dt}$

$\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )$

$= 8000 \dfrac{d}{dt}e^{0.07 \ t}$

$\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}$

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 2 years; the instantaneous rate of change is:

$\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}$

$\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

Here the amount = 12000

$12000 = (8000)e^{0.07 \ t}$

$\dfrac{12000 }{8000}= e^{0.07 \ t}$

$1.5= e^{0.07 \ t}$

㏑(1.5) = 0.07 t

0.405465 = 0.07 t

t = 0.405465 /0.07

t = 5.79

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 5.79

$\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}$

$\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

7 0

3 years ago

A referee was standing on a certain yard line as the first quarter ended. He walked 41 3/ 4 yards to a yard line with the same n

Anika [276]

43.5 yards away from the goal line.

8 0

3 years ago