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3 years ago

Rewrite as a logarithmic equation. e^(7)=y

Mathematics

1 answer:

jolli1 [7]3 years ago

5 0

E^7 = y --->(Add ln on both sides) lne^7 = ln y ---> (Bring down the power) (7)×lne = ln y ---> ( lne = 1 ) 7 = ln y

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Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma

Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with $\mu = 112$ inches and $\sigma = 14$ inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - $\mu = 112$ inches

Standard deviation - $\sigma = 14$ inches

The z-score formula is given by, $Z=\frac{x-\mu}{\sigma}$

Now,

$P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})$

$P(X>140)=P(Z>\frac{140-112}{14})$

$P(X>140)=P(Z>\frac{28}{14})$

$P(X>140)=P(Z>2)$

$P(X>140)=1-P(Z$

The Z-score value we get is from the Z-table,

$P(X>140)=1-0.9772$

$P(X>140)=0.0228$

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

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3 years ago

Two trains, Train A and Train B, weigh a total of 312 tons. Train A is heavier than Train B. The difference of their weights is

Korvikt [17]

312-170=142
142÷2=71
170+71=241
241+71=312
train A weighs 241 tons

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3 years ago

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djyliett [7]

Answer:it is b

Step-by-step explanation:

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2 years ago

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