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allochka39001 [22]
3 years ago
12

Pete wants a lone of $1,500. Which of these terms describes the money he wants to borrow?

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
4 0
Principle refers to the size of the loan.

So I believe Principle would be the right answer
mr Goodwill [35]3 years ago
3 0

Principal refers to the size of a loan.


I believe, the answer would be <em>Principal</em>.  

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PLEASE HELP, PICTURE ATTACHED! ANSWER CHOICE!
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The answer is D. 13 Inches, this is 6th grade math I believe?

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A shipping company damaged 15 packages. Each package was valued at $175.50. Which expression represents this situation?
Allushta [10]

Answer: A

Step-by-step explanation:

15 packages damaged. Cost is -175.50 this is a loss. So 15x(-175.50)

3 0
3 years ago
What is the value of f(7)
Lelu [443]

Answer:

7<em><u>f</u></em>

Step-by-step explanation:

You move 7 to the left of <em>f. </em>

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The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,
klasskru [66]

Given:

The scale factor is s=\dfrac{1}{3} and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

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Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

According to the given information, the scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

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And,

\dfrac{1}{3}(n-2)+2=4

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Therefore, the coordinates of point A are (16,8).

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Yes, but what is the question
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