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3 years ago

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A practice pool is shown. A coach walks from point A to point B to Point C. A swimmer swims directly from point A to C. Who is t

raveling the greater distance and by how much?

1 answer:

ira [324]3 years ago

7 0

Answer:

C (I Think)

Step-by-step explanation:

You might be interested in

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago

Please help me and Katie don’t delete it

artcher [175]

Answer:

A.

I say this is the answer because if she has gotten into a habait of buying and breaking glasses,shes just very careless

8 0

3 years ago

Shane wants to plant 28 marigold plants and 36 rose plants in his garden. What is the greatest number of rows possible if each r

Dennis_Churaev [7]

Answer:

HCF=2*2=4

Step-by-step explanation:

Given : Shane wants to plant 28 marigold plants and 36 rose plants in his garden

To Find : the greatest number of rows possible each row has the same

number of marigold plants and the same number of rose plants.

Solution:

marigold plants = 28

rose plants = 36

To find the greatest number of rows possible if each row has the same

number of marigold plants and the same number of rose plants.

we need to find HCF of 28 and 36

28 = 2 x 2 x 7

36 = 2 x 2 x 3 x 3

HCF = 2 x 2 = 4

greatest number of rows possible is 4

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5. On a school trip, 56 and 98 went to Kanyakumari. They ...

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If the HCF of (p²-p-6) and (p²+3p-18) is (p-a). Find the value of a ...

brainly.in/question/7765835

6 0

3 years ago

Perform the indicated operation 11/b-7 - 2b-3/b-7 = ___

statuscvo [17]

Answer:

-2(b^2 + 7b - 4)/b

Step-by-step explanation:

You need to simplify the expression

8 0

3 years ago

Lena has started painting her room. She is down to her last can of paint. The cans of paint that she is using are 11 inches tall

MrRissso [65]

Answer:

110.25π $in^{3}$

Step-by-step explanation:

The can is a circular cylinder and has the formula for the volume to be

V = $\pi r^{2} h$

r = 3.5 and h = 11

Since the paint is now 2 in. from the top of the can, then there are 9 in. left in the can, which means there is 9/11 of the total volume in the can.

Therefore, $V = (9/11)\pi (3.5^{2} )(11)$

we get V = (9/11)(12.25)(11)π

= 110.25π $in^{3}$

3 0

2 years ago